In: Statistics and Probability
What is the probability of randomly selecting a woman with green eyes and a man with children, P(green-eyed woman and a man with children)?
WOMEN EYE COLOR CHILDREN
18 Brown No
22 Brown Yes
09 Blue No
21 Blue Yes
12 Green No
18 Green Yes
MEN EYE COLOR CHILDREN
24 Brown No
16 Brown Yes
12 Blue No
18 Blue Yes
10 Green No
20 Green Yes
Solution :
We are given the table of women and men and we have to find the probability of randomly selecting a woman with green eyes and a man with children,
Since, green-eyed woman and a man with children are independent, so
P(green-eyed woman and a man with children) = P(green-eyed woman)*P(man with children)
Now,
P(green-eyed woman) = number of green eye woman / total number of woman
= 30/100 = 0.3
and P(man with children) = number of man with children / total number of man
= 54/100 = 0.54
Therefore, P(green-eyed woman and a man with children) = 0.3*0.54 = 0.162
Hence, the probability of randomly selecting a woman with green eyes and a man with children is 0.162