1, Find the Z-scores that separate the middle 59% of the
distribution from the area in the tails of the standard normal
distribution..
The Z-scores are
2, The number of chocolate chips in an 18-ounce bag of
chocolate chip cookies is approximately normally distributed with
mean 1252 and standard deviation 129 chips.
(a) What is the probability that a randomly selected bag
contains between 1000 and 1400
chocolate chips?
(b) What is the probability that a randomly selected bag
contains...
1) Find the z-scores that separate the middle 81% of the
distribution from the area in the tails of the standard normal
distribution. STEPS ON HOW TO SOLVE IT IN TI83
2) Assume the random variable X is normally distributed with
mean u=5050 and standard deviation sigmaσequals=7.
Compute the probability. Be sure to draw a normal curve with the
area corresponding to the probability shaded.
P(56 less than or equals≤X less than or equals≤67). HOW TO
ENTER IT IN TI...
Find the z-scores that cut off the middle 75% of a
normal distribution.
a) ± 0.68
b) ± 1.04
c) ± 1.15
d) ± 1.50
In a normal distribution with a mean = 10 and standard
deviation = 2, what raw score corresponds to a z-score of
1.67?
a) 13.34
b) 6.66
c) 12.16
d) 8.28
With a -zscore of -2.0 and a raw score of 35, Lenny is
asked by his professor to compute the standard deviation for a...
What are the z-scores that mark the middle 95% of this
distribution?
What is the raw score associated with the z-score below the
mean calculated in the above question?
What is the raw score associated with the z-score above the
mean calculated in the 1st question?
What is the median of this z-score distribution
A. Construct a z distribution to find the area above z =
1.75
B. Construct a z distribution to find the area below z =
-1.75
C. Construct a normal distribution with a mean of 50 and
standard deviation of 10 to find the area above x =
67.5
D. Explain why your answers to A, B, and C are all the
same.
Find the area under the standard normal distribution curve:
a) Between z = 0 and z = 1.95
b) To the right of z = 1.99
c) To the left of z = -2.09
How would I do this?
Find the area under the standard normal distribution curve:
a) Between z = 0 and z = 1.95
b) To the right of z = 1.99
c) To the left of z = -2.09
How would I do this?