What two z scores cut off the middle 95% of the normal distribution?

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orchestra answered 1 year ago

Find the z-scores that cut off the middle 75% of a normal distribution. a) ± 0.68...

Find the z-scores that cut off the middle 75% of a normal distribution. a) ± 0.68 b) ± 1.04 c) ± 1.15 d) ± 1.50 In a normal distribution with a mean = 10 and standard deviation = 2, what raw score corresponds to a z-score of 1.67? a) 13.34 b) 6.66 c) 12.16 d) 8.28 With a -zscore of -2.0 and a raw score of 35, Lenny is asked by his professor to compute the standard deviation for a...

What are the z-scores that mark the middle 95% of this distribution? What is the raw...

What are the z-scores that mark the middle 95% of this distribution? What is the raw score associated with the z-score below the mean calculated in the above question? What is the raw score associated with the z-score above the mean calculated in the 1st question? What is the median of this z-score distribution

What z-scores bound the middle 94% of the standard normal distribution? Round your answers to two...

What z-scores bound the middle 94% of the standard normal distribution? Round your answers to two decimal places. Left endpoint: right endpoint: For a random variable x which is normally distributed with mean 9.39 and standard deviation 1.7 Q1 = The number of widgets produced by a particular machine in one day is approximately normally distributed with mean 85.84 and standard deviation 12.95. What is the 32th percentile? (Round your answer to four decimal places.) Scores on a recent Stat...

Determine the two z-scores that divide the area under the standard normal curve into a middle...

Determine the two z-scores that divide the area under the standard normal curve into a middle 0.19 area and two outside 0.405 areas.

Assume a normal distribution for each question. (a) What proportion of the distribution consists of z-scores...

Assume a normal distribution for each question. (a) What proportion of the distribution consists of z-scores greater than 0.25? ( b) What is the probability of obtaining a z-score less than 0.50? ( c) What is the probability of obtaining a z-score greater than −1.50? (d) What is the probability of obtaining a z-score between +1.00 and −1.00?

Find the z-scores that separate the middle 31% of the distribution from the area in the...

Find the z-scores that separate the middle 31% of the distribution from the area in the tails of the standard normal distribution.

33. a. What z score cuts off the bottom 2.5% of all scores in the normal...

33. a. What z score cuts off the bottom 2.5% of all scores in the normal distribution? b. If shoe size in humans has a mean of µx = 10.4 and a standard deviation of σx = 1.8, and Rodney has a shoe size of 8.9, what proportion of humans have shoes larger than Rodney? c. What happens to the standard error of x̅ as sample size increases? Show all work

1, Find the Z-scores that separate the middle 59% of the distribution from the area in...

1, Find the Z-scores that separate the middle 59% of the distribution from the area in the tails of the standard normal distribution.. The Z-scores are 2, The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with mean 1252 and standard deviation 129 chips. (a) What is the probability that a randomly selected bag contains between 1000 and 1400 chocolate chips? (b) What is the probability that a randomly selected bag contains...

1) Find the z-scores that separate the middle 81% of the distribution from the area in...

1) Find the z-scores that separate the middle 81% of the distribution from the area in the tails of the standard normal distribution. STEPS ON HOW TO SOLVE IT IN TI83 2) Assume the random variable X is normally distributed with mean u=5050 and standard deviation sigmaσequals=7. Compute the probability. Be sure to draw a normal curve with the area corresponding to the probability shaded. P(56 less than or equals≤X less than or equals≤67). HOW TO ENTER IT IN TI...

in the Standard Normal distribution: (a) 2.09% of z-scores are less than z=z= (b) 17.79% of...

in the Standard Normal distribution: (a) 2.09% of z-scores are less than z=z= (b) 17.79% of z-scores are greater than z=z= In each case, round your answers to at least two decimal places. Among smartphone owners 26-35 years of age, the average number of text messages sent per day follows an approximately Normal distribution with a mean of 66 and a standard deviation of 2. (a) What percent of smartphone owners 26-35 years of age sent an average of more...

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