In: Accounting
Problem #32) Diamond Jewelers is trying to determine how to advertise in order to maximize their exposure. Their weekly advertising budget is $10,000. They are considering three possible media: TV, newspaper, and radio. Information regarding cost and exposure is given in the table below:
| 
 Medium  | 
 audience reached per ad  | 
 cost per ad ($)  | 
 maximum ads per week  | 
| 
 TV (T)  | 
 7,000  | 
 800  | 
 10  | 
| 
 Newspaper (N)  | 
 8,500  | 
 1000  | 
 7  | 
| 
 Radio (R)  | 
 3,000  | 
 400  | 
 20  | 
Based on problem #32, which of the following sets of constraints properly represent the limits on advertisements per week by media?
A) T ≤ 10; N ≤ 7; R ≤ 20
B) T ≥ 10; N ≥ 7; R ≥ 20
C) T + R + N ≤ 37
D) T + R + N ≥ 37
Based on problem #32, what is the optimal solution?
A) T = 10; N = 7; R = 20
B) T = 10; N = 0; R = 0
C) T = 10; N = 2; R = 0
D) T = 10; N = 20; R = 7
Answer 1)
Since maximum ads for T,N and R should be less than 10,7 and 20, individually, the Option A is appropriate.
The Option B limits imply that the minimum ads for T,N and R should be 10,7 and 20, which is exactly the opposite of the requirement.
Options C & D consider the limitation of ads on a total basis, which has not been required by the question. The question places limits on each ad type, not in totality.
Answer 2)
There are 2 constraints in this question:
Using Simplex function on Excel, the appropriate answer is Option C i.e. T = 10; N = 2; R = 0.
Following is the working:

Note: Please levae cells C10 - C12 blank so as to arrive at the answer using Solver.
Calculations are given as under:

The parameters are given as under:

If the use of Excel is not permitted, you may evalauate each of the options subject to the constraints mentioned above, in which case:
Thus, by virtue of elimination, Option C seems the most appropriate.
In case of any questions on the above workings, please share the same in the comments section.
All the best!