Question

In: Physics

If the mass of the ice in the test tube is m_ice=15g mass of warm water...

If the mass of the ice in the test tube is
m_ice=15g
mass of warm water used (g) = 70g
Initial temperature of water (in degrees C ) =70C
Equilibrium temperature of ice-water system (in degrees C) =44C
Calculate the calories of energy required to melt one gram of ice.

Expert Solution

Mass of ice m_ice=15g

Mass of warm water is m_w=70g

Initial temperature of water is T_i=70^oC

Final temperature of ice-water system is T_f=44^oC

Assuming ice is at 0^oC. The heat required to melt the ice is

where L is the calories of energy required to melt one gram of ice.

The energy required to increase the temperature of ice from 0^oC to T_f=44^oC is

The specific heat capacity of water is C=1cal/gram^oC

The energy required to change the temperature of warm water from T_i=70^oC to T_f=44^oC is

The heat is negative, that is, the heat is released by the warm water.

Assuming the net heat transfer to the surrounding is zero

77 calories are required to melt one gram of ice.

genius_generous answered 1 year ago

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