In: Mechanical Engineering
Given a wall that is 36 feet long and 8 feet high calculate the heat loss per hour when the inside temperature is 70 degrees inside and 10 degrees outside.
The wall assembly consists of:
A = Face brick
B = 1” Polystyrene ins. board
C = 2 X 6 studs
D = Fiberglass batt ins.
E = ½” Sheet rock
F = Paneling
In construction industry, the problems of heat transfer are solved by taking into consideration the R-values of materials used for construction. R-value is basically the measure of thermal insulation in the house.
The R-values of materials in the wall assembly for the above problem are:-
Face brick, R1 - 0.44 Ft2*F*hr/BTU
1” Polystyrene ins. board, R2 - 5 Ft2*F*hr/BTU
2 X 6 studs, R3 - 6.85 Ft2*F*hr/BTU
Fiberglass batt ins., R4 - 13 Ft2*F*hr/BTU
½” Sheet rock, R5 - 0.45 Ft2*F*hr/BTU
Paneling, R6 - 13.7 Ft2*F*hr/BTU
Total R- value = 39.44 Ft2*F*hr/BTU
Area = 36*8 Ft2 = 288 Ft2
Heat Loss/hr = (Area * Temperature difference) / Total R-value
= [ 288* (70-10) ] / 39.44
= 438.13 BTU/hr
The heat loss per hour from the given wall is observed to be 438.13 BTU/hr.