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In: Physics

The acceleration of a 5.00 kg object (a box) is described below. From t=0 to 10.00...

The acceleration of a 5.00 kg object (a box) is described below.

From t=0 to 10.00 seconds, the acceleration is time-dependent and is given by the formula: a=(0.200 m/s^3) t

From time t= 10.00 up to t=15.00 seconds, the acceleration of a box is constant and is given by the following formula: a=2.00 m/s^2

From t=15.00 up to t=25.00 seconds, the acceleration is given by a=(-0.200 m/s^3)t+5.00 m/s^2

Produce a single graph (of Force vs. time) in Excel that illustrates this. Your data should start at t=0 and go up to t=25.00 in increments of 1.00 seconds.

After you have produced the graph, calculate the impulse (J) from the graph. Note that the impulse is the area under a force v. time graph curve.

Impulse= _______ kg m/s

The acceleration of a 5.00 kg object (a box) is described below.

From t=0 to 10.00 seconds, the acceleration is time-dependent and is given by the formula: a=(0.200 m/s^3) t

From time t= 10.00 up to t=15.00 seconds, the acceleration of a box is constant and is given by the following formula: a=2.00 m/s^2

From t=15.00 up to t=25.00 seconds, the acceleration is given by a=(-0.200 m/s^3)t+5.00 m/s^2

Produce a single graph (of Force vs. time) in Excel that illustrates this. Your data should start at t=0 and go up to t=25.00 in increments of 1.00 seconds.

After you have produced the graph, calculate the impulse (J) from the graph. Note that the impulse is the area under a force v. time graph curve.

Impulse= _______ kg m/s

Expert Solution

Mistakenly I have made graph between acceleration and time it should be force vs time , actually both graph would be same except the at the place of acceleration axis there would be force axis have values mass times acceleration., Otherwise shape of graph and results would remain same..

Ask in comments if problem persist

genius_generous answered 1 year ago

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