An object with a mass of 4.15 kg undergoes an acceleration of 2.7 m/s2 for a...

An object with a mass of 4.15 kg undergoes an acceleration of 2.7 m/s2 for a period of 8.0 s. It then undergoes an acceleration of -3.2 m/s2 for a period of 20.0 s If the initial velocity of the object is 6.01 m/s and it first experiences the acceleration when it is at the origin, plot by hand on graph paper (to scale) the force, velocity, and position as functions of time. Explain why your graphs look the way they do. Include all relevant equations. (Each graph 10 pts, each explanation 10 pts, 60 pts total)

Expert Solution

Force F = ma

a is const for 0<=t<= 8 and for 8<t<=20

hence the force remain cost, over these periods and the graph is a straight line

vel v = u +at

at t=8 , v = v= 27.61 and a = -3.2 , hence the velocity increases from 0 to 8 sec in +x and then decreases and becomes -ve at t=20

x = s + ut +0.5at²

at t=0 s=0 as the object is at the origin.

a = 2.7 and hence x increases from 0 to 8 sec.

at t=8 , s =x = 134.48 and there after

x = 134 +27.61(t-8) -0.5*3.2*(t-8)²

towards the end the vel. becomes -ve and the pos reduces.

genius_generous answered 2 years ago

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