36 random samples of individuals from six different cities were asked how much time they had...

36 random samples of individuals from six different cities were asked how much time they had been spending per day watching TV. If it was found that the SSTr = 3153 and the SST = 11225, then fill out the table below (not all squares have blanks!). Whole numbered answers may be left as such, all else should be rounded to one decimal place.

Source	DF	Sum of squares	Mean squares	F	Pr > F
Treatment		3153	MSTr		0.066
Error			MSE
Total		11225

What would be the correct null and alternative hypothesis for the above situation? Type the correct letter here:

a. H₀: The hours of TV watched per day is dependent on the city.

H_a: The hours of TV watched per day is independent of the city.

b. H₀: p₁ = p₂ = p₃

H_a: at least one proportion is not equal

c. H₀: μ 1 = μ 2 = μ 3

H_a: at least one mean is different

d. H₀: μ 1 = μ 2 = μ 3

H_a: μ 1 ≠ μ 2 ≠ μ 3

e. H₀: p₁ = p₂

H_a: p₁ ≠ p₂

What would be the correct critical value if α = 5 %? Round to three decimal places.

What would be the correct conclusion if α = 5 %?

(Choose one: reject/fail to reject) the null hypothesis. There (Choose one: is/is not) enough evidence to suggest at least one of the cities watches a different amount of TV on average compared to the others.

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Expert Solution

orchestra answered 1 year ago

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