find the eigenvalues of x"+(lambda)(x) = 0, x(0)=x'(pi)=0

1a.) find the eigenvalues of x"+(lambda)(x) = 0, x(0)=x'(pi)=0

1b.) Solve ut=((c)^2)u(xx) , u(0,x)= alpha * sin x, with the boundary condition u(t,0)=u(t,pi)=0

1c.) Solve ut = u(xx), u(0,x) = alpha * sin ((pi*x)/(L)), with the boundary condition u(t,0) = u(t,L) = 0.

Expert Solution

Colby Messinger answered 1 year ago

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find the eigenvalues of x"+(lambda)(x) = 0, x(0)=x'(pi)=0

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