In: Statistics and Probability
Goop Inc. needs to order a raw material to make a special polymer. The demand for the polymer is forecasted to be normally distributed with a mean of 250 gallons and a standard deviation of 100 gallons. Goop sells the polymer for $25 per gallon. Goop purchases raw material for $10 per gallon and must spend $5 per gallon to dispose of all unused raw material due to government regulations. (One gallon of raw material yields one gallon of polymer.) If demand is more than Goop can make, then Goop sells only what it has made and the rest of the demand is lost.
a. How many gallons should Goop purchase to maximize its expected profit?
b. Suppose Goop purchases 150 gallons of raw material. What is the probability that it will run out of raw material?
c. Suppose Goop purchases 300 gallons of raw material. What are the expected sales (in gallons)?
d. Suppose Goop purchases 400 gallons of raw material. How much should it expect to spend on disposal costs (in dollars)?
e. Suppose Goop wants to ensure that there is a 92 percent probability that it will be able to satisfy its customers’ entire demand. How many gallons of the raw material should it purchase?
a)
Overage penalty = 10+5 = 15
Underage penalty = 25-10 = 15
Critical ratio = 15/(15+15) = 0.5
z = 0
Optimal order = 250
b)
µ = 250
σ = 100
P ( X ≥ 150.00 ) = P( (X-µ)/σ ≥ (150-250) /
100)
= P(Z ≥ -1.000 ) = P( Z <
1.000 ) = 0.8413
c)
Z=(X-µ)/σ= (300-250)/100)= 0.5
Expected lost sales = 100* .1978 = 19.78
Expected sales = 250 - 19.78 = 230.22
d)
Z=(X-µ)/σ= (400-250)/100)= 1.5
Expected lost sales = 100* .0293 = 2.93
Expected sales = 250 - 2.93= 247.07
Inventory = 152.93
Expected spend = 152.93 * 15 = 2293
e)
µ= 250
σ = 100
proportion= 0.92
Z value at 0.92 =
1.41 (excel formula =NORMSINV(
0.92 ) )
z=(x-µ)/σ
so, X=zσ+µ= 1.41 *
100 + 250
X = 391
Please revert in case of any doubt.
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