Question

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Consider a two-period binomial model in which a stock trades currently at $44. The stock price...

Consider a two-period binomial model in which a stock trades currently at $44. The stock price can go up 6% or down 6% each period. The risk free rate is 2% per period.

A) Calculate the price of a call option expiring in two periods with an exercise price of $45.

B) Calculate the price of a put option expiring in two periods with an exercise price of $45.

C) Based on your answer in A), calculate the number of units of the underlying stock that would be needed at t=0 in the binomial tree to construct a risk-free hedged portfolio which includes 10,000 calls.

Solutions

Expert Solution

The stock price either goes up or goes down by 6%

Let us calculate the stock price for next 2 periods -

T0 T1 T2
49.4384
46.64 up 6%
up 6% 43.8416
44 down 6%
43.8416
41.36 up 6%
down 6% 38.8784
down 6%

The Probability of going up or down is 50%

Hence probability of Prices in period 2 (T2) is 25% each

Price T2 Probability
49.4384 =50%*50% =25%
43.8416 =50%*50% =25%
43.8416 =50%*50% =25%
38.8784 =50%*50% =25%

(a) Price of Call option -  

Expected Price Probability Price after 2 periods Strike Price Call Option Value Call option Value * Probability
49.4384 25% 12.3596 45 4.4384 1.1096
43.8416 25% 10.9604 45 0 0
43.8416 25% 10.9604 45 0 0
38.8784 25% 9.7196 45 0 0
Total 100% 44 1.1096

where, Price after 2 periods= (Expected Price * Probability)

Call option value= max(Expected price-Strike price,0)

Hence, PV = 1.1096/1.022 = $1.067

(b) Price of Put option -

Expected Price Probability Price after 2 period Strike Price Put Option Value Put option Value * Probability
49.4384 25% 12.3596 45 0 0
43.8416 25% 10.9604 45 1.1584 0.2896
43.8416 25% 10.9604 45 1.1584 0.2896
38.8784 25% 9.7196 45 6.1216 1.5304
Total 100% 44 2.1096

where, Price after 2 periods= (Expected Price * Probability)

Put option value= max(Strike price-Expected price,0)

Hence, PV = 2.1096/1.022 = $2.028

(c) Let the number of stocks be x

Hence, x*44 = 10000*1.067

=> x = 242.5


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