Question

In: Physics

Consider a charge of -1 nC at (-1,0) m, and a charge of +1 nC at...

Consider a charge of -1 nC at (-1,0) m, and a charge of +1 nC at (1,0). Calculate the electric potential everywhere in the plane.

Solutions

Expert Solution

Potential due to an electric dipole

  • We already know that electric dipole is an arrangement which consists of two equal and opposite charges +q and -q separated by a small distance 2a.
  • Electric dipole moment is represented by a vector p of magnitude 2qa and this vector points in direction from -q to +q.
  • To find electric potential due to a dipole consider charge -q is placed at point P and charge +q is placed at point Q as shown below in the figure.




  • Since electric potential obeys superposition principle so potential due to electric dipole as a whole would be sum of potential due to both the charges +q and -q. Thus


    where r1 and r2 respectively are distance of charge +q and -q from point R.
  • Now draw line PC perpandicular to RO and line QD perpandicular to RO as shown in figure. From triangle POC
    cos?=OC/OP = OC/a
    therefore OC=acos? similarly OD=acos?
    Now ,
    r1 = QR?RD = OR-OD = r-acos?
    r2 = PR?RC = OR+OC = r+acos?


    since magnitude of dipole is
    |p| = 2qa


  • If we consider the case where r>>a then


    again since pcos?= p

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