A charge Q = 24 nC is fixed in space at co-ordinate (0, 0). Another charge...

A charge Q = 24 nC is fixed in space at co-ordinate (0, 0). Another charge q= 4 nC; of mass 0.07 kg, is placed at (d , 0) then let go where d = 10 nm. We need to find the speed of the charge q. Gravity should be ignored.

a) Find the potential energy U1 between the two charges when q is at (10 nm, 0). Number Units

b) Find the potential energy U2 between the two charges when q is at (d + r , 0) where d = 10 nm and r = 2 nm Number Units

c) Find the change in potential energy, ΔU = U2 - U1. Number Units

d) Do you expect ΔU to be positive or negative? Positive Negative

e) Is mechanical energy conserved ? Yes No

f) Using the conservation of energy, find the speed of q after it has moved a distance r = 2. Number Units

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Expert Solution

genius_generous answered 1 year ago

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