Question

The fuel efficiency of an aircraft’s jet engines is described by the thrust-specific fuel consumption (TSFC). The TSFC measures the rate of fuel consumption (mass of fuel burned per unit time) relative to the thrust (force) that the engine produces. In that manner, even if an engine consumes more fuel per unit time than a second engine, it is not necessarily more inefficient if it also produces more thrust to power the plane. The TSFC for an early hydrogenfueled jet engine was 0.082 (kg/h)/N. Express that value in the USCS units of (slug/s)/lb.

Answer 1

Consider the following relations.

1 kg = 6.852 × 10-2 slugs

1hr = 3600 s

1N = 0.2248 lb

 

Convert (kg/h)/N into (slugs/s)/lb

1(kg/h)/N = (0.06852 slug/3600 s)/0.2248

= 8.467 × 10-5 (slug/s)/lb

 

Convert 0.082(kg/h)/N into (slug/s)/lb

0.0829Kg/h)/N = 0.082 × 8.467 × 10-5(slug/s)/lb

= 6.943 × 10-6 (slug/s)/lb

 

Therefore 0.082(kg/h)/N is, 6.943 × 10-6 (slug/s)/lb.

Therefore 0.082(kg/h)/N is, 6.943 × 10-6 (slug/s)/lb.