Question

An order of 875mL of R/L was to infuse in 7hours at 125mL per hour. After 5 hours, 300mL of fluid was left in the IV. What would be the recalculated IV Flow rate for the remaining solution and percentage of change variation?

A client's whose BSA is 0.45m2 is to receive DRUG-M 5mg/m2 once per week. The supply dosage available is 5mg/mL. how many mL of the DRUG-M should be received per administration?

A medication, 500mg in 250mL R/L, to be infused at 10mL/hr for a patient weighing 110lbs. How many mcg/Kg/min should be infused?

A child weighs 18kg and has an order. For a drug 10mg/Kg PO stat (single dose). The oral suspension is dispensed as 200mg in 6mL. How much should be administered for one dose?

A patient needs IV 500mL of 0.9% NS over 4hr. The drop factor is 20gtt/mL. What is the Flow rate in get/min?

I NEED THIS ASAP!!!!!!!!! PLEASE

Answer 1

Answers :

Q1] 150 ml/hour.

Prescribed rate of infusion = 125 ml / hour.

Aim was to infuse 875 mL of R/L was to infuse in 7 hours.

At the end of 5 hours, fluid remaining = 300 ml.

Time left = 2 hours.

Therefore, 300 ml has to be infused in 2 hours  

The revised rate of infusion should be : 300 /120 = 150 ml / hour. (= 2.5 ml/ min).

[The percentage increase is obtained by dividing the increase by the original number and multiply the answer by 100. % increase = Increase ÷ Original Number × 100.

The percentage increase = (150-125) / 125   100 = 20 %].

Q2]  0.45 ml.

BSA of the patient = 0.45m²

Dose prescribed = 5mg/m² once per week.

Therefore, the quantity of drug required = 5 0.45 = 2.25 mg once a week.

The drug formulation available is 5 mg/ ml.

5 mg of the drug is present in1 ml of the solution.

Therefore, 2.25 mg of the drug should be present in : (1/5) 2.25 = 0.45 ml.

Q3] 6.68 mcg/kg/min.

The reconstituted solution contains 500 mg of drug in 250 ml.

Therefore,10 ml of the solution contains : (500/250) 10 = 20 mg of the drug.

Rate of infusion prescribed = 10 ml / hour.

Therefore, 20 mg i.e., 20000 mcg of the drug should be infused in 1 hour.

Weight of the patient = 110 lbs = 49.89 kg.

Therefore, rate of infusion in mcg/ kg = 20000 / 49.89 = 400.8 mcg / kg (to be infused in 1 hour).

The rate in mcg/kg/min = 400.8/60 = 6.68 mcg/kg/min.

Q4] 5.4 ml.

Dose prescribed = 10mg/Kg PO stat .

Weight of the patient = 18kg.

Therefore, the amount of drug required for the child = 10 18 = 180 mg.

Strength of the suspension = 200mg / 6mL.

6 ml contains 200 mg of the drug.

Therefore, 180 mg of the drug is present in : (6/200) 180 = 5.4 ml.

Q5] 42 ml/ min

Dose prescribed = 500 ml in 4 hours.

Drop factor = 20 drops/ ml.

That is, 1 ml contains 20 drops.

Therefore, the dose prescribed = 500 20 = 10000 drops in 4 hours.

The flow rate in drops/min = 10000/ (4 60) = 41.66 ml/ min = 42 ml/ min (approx).