In: Statistics and Probability
A warehouse employs
28
workers on first shift,
15
workers on second shift, and
10
workers on third shift.
Eight
workers are chosen at random to be interviewed about the work environment. Find the probability of choosing exactly
five
first-shift
workers.
The probability of choosing exactly
five
first-shift
workers is
nothing.
(Round to three decimal places as needed.)
Given a warehouse employs,
28 workers on first shift,
15 workers on second shift,
10 workers on third shift.
Now eight workers are chosen at random and they are to be interviewed about the work environment.
We need to find the probability of choosing exactly five first shift workers.
Now total number of workers are 53.
Now the number of ways we can choose 8 workers from 53 workers is= 53C8
The number of ways we can choose 5 first shift workers from 28 workers is=28C5
So out of the 8 workers chosen randomly we had already chosen 5 first shift workers so the remaining 3 workers should be chosen from the second or the third shift workers and that can be done in=(15+10)C3=25C3 ways
Therefore the probability of choosing exactly five first shift workers is=(28C5 * 25C3)/53C8
Therefore the probability of choosing exactly five first shift workers is 0.255