Question

In: Chemistry

A reaction A(aq) + B(aq) --> C(aq) has a standard free-energy change of –3.23 kJ/mol at...

A reaction
A(aq) + B(aq) --> C(aq)
has a standard free-energy change of –3.23 kJ/mol at 25 °C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively?

Solutions

Expert Solution

Using the standard free energy change formula, we can find the equilibrium constant for the reaction

                    

Initial              0.3M         0.4M                   0

Final            (0.3-x)M       (0.4-x)M             xM

The value of 0.826 is not possible since otherwise the conc of A and B will be negative hence the correct answer is 0.145M

Concentration of C = 0.145M

Concentation of B = (0.4 - 0.145) = 0.255M

Concentation of A = (0.3 - 0.145) = 0.155M


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