Question

URGENT!!!!!!!!!!!!!!!!!!!

Write Java code which will create a GUI window on screen. The window has one button: Doggy. When the user selects Doggy, “Bow Bow” should be printed on screen. Justify your syntax.  

Answer 1

// DoggyButton.java
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;

public class DoggyButton extends JFrame {
  
   public DoggyButton() {

       super("Doggy Button"); // pass the GUI window title
       setDefaultCloseOperation(EXIT_ON_CLOSE); // close button will exit the operation
      
       // creating a panel
       JPanel panel = new JPanel();
       // creating the button
       JButton doggy = new JButton("Doggy");
       // add the button to the panel
       panel.add(doggy);
       // add action listener to the button
       doggy.addActionListener(new ActionListener() {
           @Override
           public void actionPerformed(ActionEvent e) {
               System.out.println("Bow Bow"); // when clicked, it displays Bow Bow on console
           }
       });
      
       // add button to the panel
       add(panel);
       // using compact size
       pack();
      
   }

   public static void main(String[] args) {

       // create the GUI
       DoggyButton btn = new DoggyButton();
       btn.setVisible(true); // set the frame visible
   }

}

//end of DoggyButton.java

Output: