Question

Write Java code which will create a GUI window on screen. The window has one button: Doggy. When the user selects Doggy, “Bow Bow” should be printed on screen. Justify your syntax.

Answer 1

//Java Code

import javax.swing.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.lang.reflect.InvocationTargetException;

public class DoggyGUI extends JFrame implements ActionListener {
    //Create a label
    JLabel lblResult;
    //create a button
    JButton btnShow;
    public DoggyGUI()
    {
        lblResult = new JLabel("");
        lblResult.setBounds(120,50,80,30);
        btnShow = new JButton("Doggy");
        //set Action listener
        btnShow.addActionListener(this::actionPerformed);
        btnShow.setBounds(100,100,80,30);

        setLayout(null);
        setTitle("Doggy GUI");
        setSize(300,200);
        setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        //add label to Frame
        getContentPane().add(lblResult);
        //Add button to Frame
        getContentPane().add(btnShow);
        setVisible(true);
    }
    //Action listener
    @Override
    public void actionPerformed(ActionEvent e) {
        if(e.getSource().equals(btnShow))
        {
            //set label text
           lblResult.setText("Bow Bow");
        }
    }


    public static void main(String[] args) throws InvocationTargetException, InterruptedException {
       SwingUtilities.invokeAndWait(new Runnable() {
           @Override
           public void run() {
               new DoggyGUI();
           }
       });
    }
}

//Output

//If you need any help regarding this solution....... please leave a comment.. thanks