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In: Statistics and Probability

Average yield of strain A was measured as 0.905 by 20 experiments and average yield of...

Average yield of strain A was measured as 0.905 by 20 experiments and average yield of strain B of the same organism under same experimental conditions was measured as 0.873 by 15 experiments. Standard deviation of yields of strain A was K/1000 and standard deviation of yields of strain B was (K+15)/1000 where K is the 17. a) Construct 95% confidence interval for the ratio of population variance of yields of strain A to population variance of yields of strain B. b) Construct 99% confidence interval for the difference between population means of yields of strain A and strain B (μA- μB) c) Test the null hypothesis of equality of population means of yields of strain A and strain B against the alternative hypothesis: μA > μB (use p-value approach).

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orchestra answered 1 year ago
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