Question

A magazine collects data each year on the price of a hamburger in a certain fast food restaurant in various countries around the world. The price of this hamburger for a sample of restaurants in Europe in January resulted in the following hamburger prices (after conversion to U.S. dollars).

5.18	4.99	4.06	4.68	5.25	4.66
4.17	4.98	5.19	5.59	5.34	4.60

The mean price of this hamburger in the U.S. in January was $4.63. For purposes of this exercise, assume it is reasonable to regard the sample as representative of these European restaurants. Does the sample provide convincing evidence that the mean January price of this hamburger in Europe is greater than the reported U.S. price? Test the relevant hypotheses using α = 0.05. (Use a statistical computer package to calculate the P-value. Round your test statistic to two decimal places and your P-value to three decimal places.)

t	=
P-value	=

Answer 1

the necessary calculation table:-

x	x2
5.18	26.8324
4.99	24.9001
4.06	16.4836
4.68	21.9024
5.25	27.5625
4.66	21.7156
4.17	17.3889
4.98	24.8004
5.19	26.9361
5.59	31.2481
5.34	28.5156
4.6	21.16
sum=58.69	sum=289.4457

sample size(n) = 12

hypothesis:-

test statistic be:-

df = (n-1) = (12-1) = 11

p value :-

[ in any blank cell of excel type =T.DIST.RT(1.93,11) press enter]

decision:-

p value = 0.040 <0.05 (alpha)

so, we reject the null hypothesis.

conclusion:-

the sample provide sufficient evidence that the mean January price of this hamburger in Europe is greater than the reported U.S. price at 0.05 level of significance.

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