In: Chemistry
Consider the following chemical reaction: 2 CH4(g) 3 O2(g) 2 CO(g) 4 H2O(l) Select all the statements that are correct:
The reaction should become more product favored at high temperatures
The reaction should become more product favored at low temperatures
The reactants can adopt a larger number of configurations than the products
The potential energy of the reactants is higher than the potential energy of the products
The potential energy of the reactants is lower than the potential energy of the products
The reactants can adopt a fewer number of configurations than the products
In: Chemistry
Please show work.
A. For single reactant: observe the change in rate for a change in initial reactantconcentration.
| Reaction 1 | Reaction 2 | Reaction 3 | |||
| [A] (M) | Initial Rate (M/s) | [C] (M) | Initial Rate (M/s) | [K] (M) | Initial Rate (M/s) |
| 0.10 | 0.015 | 0.10 | 0.015 | 0.10 | 0.015 |
| 0.20 | 0.030 | 0.20 | 0.060 | 0.30 | 0.135 |
| 0.40 | 0.060 | 0.40 | 0.240 | 0.90 | 1.215 |
The table above shows three independent reactions (not related to each other). What are the rate laws for each of thesereactions?
B. For multiple reactants: Find the reaction order for each reactant separately.
| [A] (M) | [X] (M) | Initial Rate (M/s) |
| 0.050 | 0.050 | 0.014 |
| 0.150 | 0.050 | 0.056 |
| 0.050 | 0.100 | 0.028 |
| 0.150 | 0.150 | 0.168 |
For the table above, find the rate law and the rate constant. What is the overall order of the reaction?
In: Chemistry
ErmTR is an enzyme found in S. pyogenes strains that are resistant to erythromycin. While working in the lab one afternoon you discover a small molecule (C23) that inhibits the activity of ermTR. To assess the type of inhibitor you discovered, you set up reactions with 6 different concentrations of erythromycin and varying amounts of the C23 small molecule you discovered. To each reaction you add 2 x 10-12 mol of ermTR (total reaction volume: 15 mL) and measure the initial velocities, Vo, by spectrophotometry. You obtained the following data:
Initial Velocity Vo (micromoles/min)
| erythromycin | no inhibitor | 1 mM inhibitor | 2 mM inhibitor |
|---|---|---|---|
| 1 | 0.059 | 0.045 | 0.037 |
| 2 | 0.105 | 0.082 | 0.071 |
| 4 | 0.174 | 0.144 | 0.119 |
| 6 | 0.222 | 0.190 | 0.160 |
| 8 | 0.258 | 0.210 | 0.197 |
| 16 | 0.340 | 0.310 | 0.281 |
Display the data on a Lineweaver-Burk plot in order to extract
the Km and Vmax values. You can
generate the plot by hand on the graph paper on the last page or
use a program, such as Excel, to plot the data. Submit the plot you
generate with your test answers.
b) What are the KM and Vmax values for each of the samples? Show your calculations and explain how you obtain the answer for the “no inhibitor” sample.
c) What type of inhibitor is C23? Explain your answer.
d) Calculate the turnover number and the specificity constant for the enzyme sample that lacks the inhibitor C23.
In: Chemistry
11) In the reaction of nitrogen gas with hydrogen gas to form ammonia gas, NH3, bow many grams of hydrogen are needed to react with two moles of nitrogen?
In: Chemistry
The boiling point of pure ethanol at 760. torr is 82.0 degrees celsius. What would bet the vapor pressure of ethanol over a solution containing 2.13 mole of nonvolatile hydrocarbon and 15.30 moles of ethanol at 85.9 degrees celsius?
In: Chemistry
Explain causes leading to the plastic straps on a lawn chair seat, break after it has been left in sunlight for a long period of time. What types of additive can be used to prolong the life of the straps?
In: Chemistry
I am designing a mass spectrometer and the last task asks to
figure out a certain compound based on the ions the spectrometer
has found. It gives an ion ratio of 108:218:432:540 for m/z ratio
of 16:14:12:1. I know the compound is supposed to be caffiene which
has a formula of c8h10n4o2. Dividing the number of ions by 54 gives
me the appropriate chemical formula, but I do not know the
reasoning behind why I would divide by 54. I was wondering if
someone could explain to me, based on the number of ions detected,
how I would arrive to the chemical formula for caffeine?
In: Chemistry
You did a reaction and it resulted in the following mixture of compounds:
(Benzoic ring, benzoic ring with OH, Benzoic ring with COOH)
What would you do to isolate and then purify benzoic acid?
How would you prove that your final product is pure?
Which peaks in the IR and NMR you would look for to see if you got indeed benzoic acid? Mention all, but also specify the peaks that are different from peaks the other compounds have as well.
In: Chemistry
what is the pH of a solution following the combination of 245.0 mL of a 4.00*10^-3 M NaOH solution with 255.0 mL of a 2.33*10^-3 M H2SO4 solution?
In: Chemistry
100 moles of ethane (C2H6) are burned with 50% excess air. The percentage conversion of the ethane is 90%; of the ethane burned, 25% reacts to form CO and the balance reacts to form CO2. Calculate the molar composition of the stack gas on a dry basis and the mole ratio of water to dry stack gas.
In: Chemistry
PART B ONLY<
The Ideal Gas Law and Stoichiometry The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH3) over a catalyst with excess oxygen (O2) to produce nitrogen monoxide (NO) gas as shown by the unbalanced equation given here: ?NH3(g)+?O2(g)→?NO(g)+?H2O(g)
Part A What volume of O2 at 912 mmHg and 33 ∘C is required to synthesize 16.0 mol of NO?
volume of O2 = 419 L
Part B
What volume of H2O(g) is produced by the reaction under the same conditions? Express your answer to three significant figures and include the appropriate units. volume of H2O =
In: Chemistry
Calculate the concentrations of all species in a 1.49 M Na2SO3 (sodium sulfite) solution. The ionization constants for sulfurous acid are Ka1 = 1.4× 10–2 and Ka2 = 6.3× 10–8. [Na+]= [SO3^2-]= [HSO3^-]= [H2SO3]= [OH^-]= [H^+]=
In: Chemistry
One turn of the CAC only produces one ATP (or GTP). Explain how most of the energy of the four oxidation steps in the CAC is conserved?
Please help explain and where could I find more information on this
In: Chemistry