Match the pollutants on the left with effects or other significant aspects on the right:

What mass of nitrogen is needed to fill an 855 L tank at STP?

Arsenious acid is a weak acid:

HAsO₂<-> H⁺+AsO₂^- pKa=9.22

If 10^-3 moles of the herbicide NaAsO₂ are added to 1 liter of water at 25 degrees Celsius, what is the resulting pH? Determine your answer algebraically using appropriate assumptions or using iterative calculations in a spreadsheet.

How many grams of silver chloride can be prepared by the reaction of 107.0 mL of 0.21 M silver nitrate with 107.0 mL of 0.14 M calcium chloride?

Calculate the concentrations of each ion remaining in solution after precipitation is complete.

For the reaction

2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g).  E∘=0.71 V

what is the cell potential at 25 ∘C if the concentrations are [Co3+]= 0.634 M , [Co2+]= 0.385 M , and [Cl−]= 0.491 M and the pressure of Cl2 is PCl2= 6.10 atm ?

For the reaction
A + B + C → D
The following data were obtained at constant temperature:

1. What is the order with respect to each reactant? (Enter the order for A as Answer 1, that for B as Answer 2, and that for C as Answer 3. You must get all 3 correct.)

2. What is the value of the rate constant for the reaction at this temperature?

Exercise 15.82

For each of the following strong base solutions, determine [OH−],[H3O+], pH, and pOH.

Part A

8.74×10⁻³ M LiOH

Express your answer using three significant figures. Enter your answers numerically separated by commas.

[OH−],[H3O+] =

Part B

Express your answer to three decimal places. Enter your answers numerically separated by commas.

pH,pOH =

Part C

1.12×10⁻² M Ba(OH)2

Express your answer using three significant figures. Enter your answers numerically separated by commas.

[OH−],[H3O+] =

Part D

Express your answer to three decimal places. Enter your answers numerically separated by commas.

pH,pOH =

Part E

2.2×10⁻⁴ M KOH

Express your answer using two significant figures. Enter your answers numerically separated by commas.

[OH−],[H3O+] =

Part F

Express your answer to two decimal places. Enter your answers numerically separated by commas.

pH,pOH =

Part G

4.8×10⁻⁴ M Ca(OH)2

Express your answer using two significant figures. Enter your answers numerically separated by commas.

[OH−],[H3O+] =

Part H

Express your answer to two decimal places. Enter your answers numerically separated by commas.

pH,pOH =

please read the material underneath is not clear to me how to aproach this am not a chem major so its kind of hard. thanks for the help

In Part I, when the solution containing aluminum and sodium hydroxide is heated under the hood, why should you wait until the “fizzing” stops?

In Part I, item #8, what is the purpose of the centrifuge?

To speed the process of settling the aluminum hydroxide gel.

Would it be safe for you to drink the water from today’s experiment?

Why or Why not?

CLARIFICATION OF WATER

One of the steps that must be performed on water to make it suitable for drinking is that any suspended solid material must be removed from the water. Suspended solids are materials such as very fine dirt particles that are carried along by, but not truly dissolved in the water. One way to remove suspended particles is to use a type of chemical called a flocculant that combines with the suspended solids to form a mass or floc that is solid enough to be filtered out of the water. Water treatment plants use several different flocculants to remove suspended solids. In this experiment, you will prepare one f1occulant, aluminum hydroxide [Al(OH) ₃] from aluminum metal and then use the aluminum hydroxide to clarify (remove the suspended solids from) some dirty water. Taking used aluminum cans and preparing aluminum hydroxide from them is one possible use for the old cans, but turning the cans into new aluminum cans is a more economical way to recycle the aluminum.

The reactions involved in this experiment are:

Dissolving aluminum metal with sodium hydroxide solution:

Al +      2 Na⁺         +      2 OH^-      +    6 H₂O →    2 Na⁺    +   2 Al(OH)₄^-          +       3 H₂ (g)

Converting the aluminum ion into aluminum sulfate (aluminum and sulfate ions in solution):

Al(OH)₄^- +      4 H₂SO_{4         →}        2 Al³⁺     +     4 SO₄^2-      +     8 H₂O

Converting the aluminum sulfate solution into solid aluminum hydroxide:

Al³⁺ +    6 OH^-       _→        2 Al(OH)₃ (s)

The hydroxide ions used in step 3 come from the reaction of sodium hydrogen carbonate (also known as sodium bicarbonate or baking soda) when it is dissolved in water:

                                NaHCO₃ (s) +            H₂O _→   Na⁺    +    OH^-    +     CO₂ (g)   +     H₂O

Another type of material that sometimes must be removed from water before it can be used for drinking is a dissolved chemical. If the dissolved molecules are large enough, they can be removed by passing the water over a form of carbon called activated charcoal. Activated charcoal has a very large surface area and this surface is able to latch onto (absorb) certain dissolved materials and hold onto them. The charcoal, along with the chemicals it has caught, can, then be filtered out of the water. After the charcoal has been filtered from the water, it can be made ready to be used again by heating it with steam (500- 1000 °C). This causes the charcoal to release the absorbed chemicals leave clean charcoal that can be used again.

                                                                                     43

PROCEDURE:

PREPARATION AND USE OF ALUMINUM HYDROXIDE

Weigh out 0.20 g of aluminum foil and put it into a 250 mL beaker.

Measure out 15 mL of 6 M sodium hydroxide (NaOH) solution and pour it over the aluminum foil in the beaker. Make sure that the foil is completely covered by the solution.

Put the beaker on a hot plate in the fume hood and GENTLY heat the mixture. Do not boil. Stir the mixture to keep it from foaming over.

Continue warming the solution until most of the fizzing stops (about five minutes). Remove the beaker from the hot plate and allow it to cool.

Add 20 mL of 3 M sulfuric acid (H₂S04) to the beaker and stir the mixture well to dissolve as much of the gel-like material as possible.

Suction filter the mixture using a Büchner funnel as your instructor will demonstrate. Be sure that the filter paper lies flat on the bottom of the Büchner funnel. Wet the filter paper slightly with deionized water to help flatten the filter paper. Take the filtrate (the liquid that went through the filter paper into the flask) and pour it into a 150 mL beaker.

Add 10 mL of the filtrate to 10 mL of the dirty water provided in a 100 mL beaker. Add solid sodium hydrogen carbonate slowly, with stirring; until the liquid is basic to litmus. Stir well and pour some of the slurry into a centrifuge tube and label it tube "1."

The aluminum hydroxide gel will settle out over time with its trapped "dirt," but we can speed up the process by using a centrifuge. Using untreated dirty water, fill a second centrifuge test tube (tube "2") to the same level as tube "1." Put the tubes in the centrifuge on opposite sides and centrifuge them for two minutes.

Decant the liquid from the centrifuge tubes into spectrophotometer tubes labeled “1” and “2”. Fill a third spectrophotometer test tube (tube "3") with untreated dirty water to the same height as the other two tubes. Compare the absorbance at 500 nm of each solution using a spectrophotometer. Record the results on the lab report form.

Put the waste from this part of the experiment into the waste beaker provided.

USE OF ACTIVATED CHARCOAL

Take two Erlenmeyer flasks of the same size and add 50 mL of deionized water to each flask. Add five drops of methylene blue dye solution to each flask.

Add about 0.5 g of activated charcoal to one of the flasks. Swirl the flask to mix the water and charcoal well.

Filter the charcoal from the water using the suction filtration method used earlier and compare the appearance of the treated water with the untreated water that still has methylene blue in it. Record the results on the lab report form.

The liquid waste from this part of the experiment can be rinsed down the drain.

Please Show working for the following clearly

4.) Barium hydroxide is reacted with calcium iodide. Calculate how many mL of .30M Ba (OH)2 needed to react with 250mL of .50M Cal2 (Write balanced equation first).

5.) Given the equation; N2 (g) + 3H2(g) (arrow) 2NH3(g). If 7.00L of N2 ( at STP) reacts with 15.0 L of H2, A.) How many L of NH3 is formed? B.) How many L of the excess gas remains unreacted?

C.) How many grams of NH3 are formed?

A.)

B.)

C.)

6.) In the titration, HBr + KOH (arrow) H2O + KBr, if 48.5 mL of 1.5M HBr reached the end point of 50.0mL of the KOH, calculate the molarity of the KOH.

What is the significance of the Fermi wavelength in terms of the optical property of the nanomaterial?

Imagine that a polluter starts dumping sodium chloride into Lake Charles at a rate of 1413.7 kg per day, that the background concentration of NaCl in the lake was 8.3 ppm, and that the residence time of NaCl in the lake is 3.5 years. After 5 years, the Environmental Protection Agency catches on and turns off this source of NaCl. What would be the maximum concentration of NaCl in the lake? Please give your answer in ppm. Lake Charles has a volume of 1.8*107 m3.

the following equilibrium reaction occurs in aqueous solutions when 0.1 M KSCN is mixed with 0.1 M

Fe(NO3)3. Fe(SCN)2+(aq) <----> Fe3+(aq) + SCN-(aq)

Predict whether the following statements (in relation to the above equilibrium reaction in aqueous solution) are "True" or "False".

1.Addition of 0.1 M NaNO3 does not have as much influence on the position of the equilibrium.

2.Addition of 0.1 M KSCN does not affect the position of the equilibrium.

3.Addition of 0.1 M KNO3 causes the equilibrium to shift to the left (reactant side).

4.Addition of 0.1 M Fe(NO3)3 causes the equilibrium to shift to the right (product side).

5.In the addition of 6 M NaOH, OH- reacts with Fe3+ to form slightly soluble Fe(OH)3.

6.Addition of 0.1 M LiSCN will have a similar effect on the position of the equilibrium as the addition of 0.1 M KSCN.

7.Addition of 6 M NaOH causes the equilibrium to shift to the left because NaOH is a strong base and breaks the bonds in Fe(SCN)2+

Describe and explain the bonding (sigma and/or pi interactions) in Fe(NO)₂(CO)₂

The sequence of a polypeptide X is as follows:
THCARKEDSGYPEWANVRDECW

1. The Optical Density (O.D.) at 280 nm of a solution of the above polypeptide X is 0.51 at the standard experimental conditions (i.e. optical length L = 1.0 cm) . What is the concentration of the polypeptide X in this solution (in mM)? (The molar absorptivity (e) for tyrosine and tryptophan residues at 280 nm are 1,400 M^(-1)cm^(-1) and 5,500 M^(-1)cm^(-1), respectively).

2. Estimate the molecular weight of this peptide.

3. Draw side-chain structures and peptide bonds for the first five amino acid residues of the polypeptide X.