Question

In: Chemistry

Assuming standard conditions, answer the following questions. (Use the table of Standard Reduction Potentials for common...

Assuming standard conditions, answer the following questions. (Use the table of Standard Reduction Potentials for common Half-reactions from your text. If hydrogen is one of the reagents, assume acidic solution.)

1) Is Cr3+(aq) capable of oxidizing Fe2+(aq) to Fe3+(aq)?

2) Is Cr metal capable of reducing Fe2+(aq)?

3) Is Sn metal capable of reducing Fe3+(aq) to Fe2+(aq)?

4)Is H2(g) capable of reducing Ni2+(aq)?

5) Is Fe2+(aq) capable of reducing Cr3+(aq) to Cr metal?

6)Is VO2+(aq) capable of oxidizing Fe2+(aq)?

Solutions

Expert Solution

1) Is Cr3+(aq) capable of oxidizing Fe2+(aq) to Fe3+(aq)?

Fe3+ + e− <-> Fe2+ 0.77

Cr3+ + e−<-> Cr2+ −0.42

The reaction:

Fe3+ + e− <-> Fe2+ E = 0.77

Cr2+ <->Cr3+ + e- E = −0.42

From, here, Cr+3 will OXIDIZE and Fe will reduce: therefore the answer is NO

2) Is Cr metal capable of reducing Fe2+(aq)?

Cr3+ + 3 e− <--> Cr(s) −0.74

Fe2+ + 2 e− <-> Fe(s) −0.44

the reaction that occurs spontanously:

Cr(s) <-> Cr3+ + 3 e− E = 0.74

Fe2+ + 2 e− <-> Fe(s) E = −0.44

then, Chromium will reduce Fe+2; answer is YES

3) Is Sn metal capable of reducing Fe3+(aq) to Fe2+(aq)?

Fe3+ + e− <-> Fe2+ E = 0.77

Sn2+ + 2 e− <-> Sn(s) −0.13

this will occurs spontaneously:

Fe3+ + e− <-> Fe2+ E = 0.77

Sn(s) <-> Sn2+ + 2 e− E = 0.13

Sn is being oxidized and reduces Fe, therefore the statement is TRUE

4)Is H2(g) capable of reducing Ni2+(aq)?

Ni2+ + 2 e− <-> Ni(s) −0.25

2 H+ + 2 e− <-> H2(g) 0.0000

then this occurs spontaneously

Ni(s) <-> Ni2+ + 2 e− E = 0.25

2 H+ + 2 e− <-> H2(g) 0.0000

that is, Nickel is reducing, therefore the answer is NO

5) Is Fe2+(aq) capable of reducing Cr3+(aq) to Cr metal?

Cr3+ + 3 e− <--> Cr(s) −0.74

Fe2+ + 2 e− <-> Fe(s) −0.44

the reaction that occurs spontanously:

Cr(s) <-> Cr3+ + 3 e− E = 0.74

Fe2+ + 2 e− <-> Fe(s) E = −0.44

answer is NO, Fe+2 will oxidize Chromium

6)Is VO2+(aq) capable of oxidizing Fe2+(aq)?

VO2+ + 2 H+ + e−<-> V3+ + H2O +0.34

Fe2+ + 2 e− <-> Fe(s) E = −0.44

this will occur spontaneously

VO2+ + 2 H+ + e−<-> V3+ + H2O +0.34

Fe(s) <->Fe2+ + 2 e−    E = +0.44

then, the answer is YES; VO+2 will oxidize Fe


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