Question

Consider that you have a water park and a slide with no friction in it . Park visitors slide a vertical distance hh down the waterslide in a sitting position. When they come to the bottom of the slide, they grab a handle at the bottom end of a 5.00-m-long uniform pole. The pole hangs vertically, initially at rest. The upper end of the pole is pivoted about a stationary, frictionless axle. The pole with a person hanging on the end swings up through an angle of 70.0∘∘, and then the person lets go of the pole and drops into a pool of water. Treat the person as a point mass. The pole's moment of inertia is given by I=1/3 ML^2 , where L = 6.00 m is the length of the pole and M = 40.0 kg is its mass.

For a person of mass 70.0 kg, what must be the height hh in order for the pole to have a maximum angle of swing of 60.0∘ after the collision?

Answer 1