In: Economics
Suppose that BMW can produce any quantity of cars at a constant marginal cost equal to $20,000 and a fixed cost of $10 billion. You are asked to advise the CEO as to what prices and quantities BMW should set for sales in Europe and in the United States. The demand for BMWs in each market is given by: QE = 4,000,000 ? 100PE and QU = 1,000,000 ? 20PU where the subscript E denotes Europe and the subscript U denotes the United States. Assume that BMW can restrict U.S. sales to authorized BMW dealers only. a. What quantity of BMWs should the firm sell in each market, and what should the price be in each market? b. What should the total profit be? c. If BMW were forced to charge the same price in each market, what would be the quantity sold in each market, the equilibrium price, and the company’s profit?
(a)
In Europe,
QE = 4,000,000 - 100PE
100PE = 4,000,000 - QE
PE = 40,000 - 0.01QE
Total revenue (TRE) = PE x QE = 40,000QE - 0.01QE2
Marginal revenue (MRE) = dTRE/dQE = 40,000 - 0.02QE
Equating MRE & MC,
40,000 - 0.02QE = 20,000
0.02QE = 20,000
QE = 1,000,000
PE = 40,000 - (0.01 x 1,000,000) = 40,000 - 10,000 = $30,000
In US,
QU = 1,000,000 - 20PU
20PU = 1,000,000 - QU
PU = 50,000 - 0.05QU
Total revenue (TRU) = PU x QU = 50,000QU - 0.05QU2
Marginal revenue (MRU) = dTRU/dQU = 50,000 - 0.1QU
Equating MRU & MC,
50,000 - 0.1QU = 20,000
0.1QU = 30,000
QU = 300,000
PU = 50,000 - (0.05 x 300,000) = 50,000 - 15,000 = $35,000
(b)
Aggregate revenue (TR) ($ Million) = TRE + TRU = (PE x QE) + (PU x QU) = (30,000 x 1) + (35,000 x 0.3)
= 30,000 + 10,500 = 40,500
Total cost ($ Million) = MC x (QE + QU) - Fixed costs = 20,000 x (1 + 0.3) - 10,000 = 20,000 x 1.3 - 10,000
= 26,000 - 10,000 = 16,000
Profit ($ Million) = TR - TC = 40,500 - 16,000 = 24,500
(c) In absence of price discrimination, PE = PU = P and market demand (Q) = QE + QU
Q = 4,000,000 - 100P + 1,000,000 - 20P
Q = 5,000,000 - 120P
120P = 5,000,000 - Q
P = (5,000,000 - Q) / 120
TR = P x Q = (5,000,000Q - Q2) / 120
MR = dTR/dQ =(5,000,000 - 2Q) / 120
Equating MR & MC,
(5,000,000 - 2Q) / 120 = 20,000
5,000,000 - 2Q = 2,400,000
2Q = 2,600,000
Q = 1,300,000
P = (5,000,000 - 1,300,000) / 120 = 3,700,000 / 120 = $30,833
QE = 4,000,000 - (100 x 30,833) = 4,000,000 - 3,083,333 = 916,667
QU = 1,000,000 - (20 x 30,833) = 1,000,000 - 616,660 = 383,340
Profit ($ Million) = Q x (P - MC) - FC = 1.3 x (30,833 - 20,000) - 10,000 = 1.3 x 10,833 - 10,000 = 14,082.9 - 10,000
= 4,082.9