In: Finance
a. Cecila on her 21st birthday has 25000 * (100%+6%)^21 = $84,989
b. Wade - If depositing at the start of the months - $7,912. If depositing at end of months - $8,018
Monthly requirement | (7,992) | =PMT(0.33%,24,,200000,1) |
Interest per month | 0.33% | |
Time in months | 24 | |
Amount required | 200,000 |
c. Julie and Miguel require to invest $8,219 today to have $10,000 in 5 years
Amount required | 10,000 | |
Interest | 4.00% | |
Period in years | 5 | |
Amount to be invested | 8,219 | =10000/(1+4%)^5 |
d. Bonus : Amount at the end of 3rd year = $37,091 (assuming that bonus will be received at year ends and amount is required at the end of 3rd year)
Yearly amount | 12,000 | |
years | 3 | |
Annual interest rate | 3% | |
Amount at end of 3 years | 37,091 | =12000+12000*(1+D16)+12000*(1+D16)^2 |
e. Santiago: Amount to be invested at start of each month till 1.5 years =$189
Monthly requirement | (189) | =PMT(0.33%,24,,200000,0) |
Interest per month | 0.33% | |
Time in months | 18 | |
Amount required | 3,500 |
f. Margaret : approximately 5.4 years (63.87 months)
Amount at period 0 | 6,500 |
Amount at end | 12,600 |
Interest per month | 1.04% |
Months | 63.87 |
g. Brian : Interest rate = 11.57% approximately
Value at start of year 1 | 1800 | |
Value at end of year 3 | 2500 | |
Period in years | 3 | |
Interest rate | 11.57% | =(2500/1800)^(1/3)-1 |
h. Carol : Monthly payment of approx. $1,461
Total loan (400,000 * 70%) | 280,000 | |
Period in months | 360 | |
Interest rate monthly | 0.3958% | |
Monthly payments | ($1,460.61) | =PMT(0.3958%,360,280000,,) |
Interest paid | (245,821) |
i. Yearly investment of $150 at year end @ approximately 14.4% will accumulate $1,000 over 5 years
j. Car purchase
Amount today | 15,000 | |
Interest rate | 8% | |
Years | 3 | |
Amount at end of 3 years with interest | 18,896 | =15,000*(1+8%)^3 |
Amount required at end of 3 years | 23,000 | |
Additional mount required | 4,104 |
k. Manufacturer : Right now you should accept $4,080 in lieu of the annual payments
Interest rate | 7% | ||
Period | amounts to be received | Present value | |
right now | 800 | 800 | =800/(1+7%)^0 |
in 1 year from now | 800 | 748 | =800/(1+7%)^1 |
in 2 years from now | 800 | 699 | =800/(1+7%)^2 |
in 3 years from now | 800 | 653 | =800/(1+7%)^3 |
in 4 years from now | 800 | 610 | =800/(1+7%)^4 |
in 5 years from now | 800 | 570 | =800/(1+7%)^5 |
Total | 4,080 |
l. It will take slightly more than 5 years to accumulate $7,000 by investing $1,000 annually.