Given the fact that the lifetime of 14C, the radioactive isotope of carbon, is approximately 8267...

Given the fact that the lifetime of ¹⁴C, the radioactive isotope of carbon, is approximately 8267 years, calculate how much time would pass before only 83.5% of the initial amount of the ¹⁴C remains. (Note: the lifetime = half life/ln (2) = half life/0.6931. The half life of ¹⁴C is 5730 years.)

Decay Time (in years):

Expert Solution

genius_generous answered 2 years ago

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