Question

In: Computer Science

Implement a stack using a single queue. In particular, you are given a queue Q that...

Implement a stack using a single queue. In particular, you are given a queue Q that provides the method Q.size() to return its size at any point and the standard methods of queues (i.e, Q.enqueue(x) and Q.dequeue()). The requirement is to use such methods of Q to implement two methods S.push(x) and S.pop() for a stack S. What are the running times of your methods?

Kindly answer using python programming

Solutions

Expert Solution

class Stack:
    def __init__(self):
        self.q = Queue()
 
    def is_empty(self):
        return self.q.is_empty()
 
    def push(self, data):
        self.q.enqueue(data)
 
    def pop(self):
        for _ in range(self.q.get_size() - 1):
            dequeued = self.q.dequeue()
            self.q.enqueue(dequeued)
        return self.q.dequeue()
 
 
class Queue:
    def __init__(self):
        self.items = []
        self.size = 0
 
    def is_empty(self):
        return self.items == []
 
    def enqueue(self, data):
        self.size += 1
        self.items.append(data)
 
    def dequeue(self):
        self.size -= 1
        return self.items.pop(0)
 
    def get_size(self):
        return self.size
 
 
s = Stack()
 
print('Menu')
print('push <value>')
print('pop')
print('quit')
 
while True:
    do = input('What would you like to do? ').split()
 
    operation = do[0].strip().lower()
    if operation == 'push':
        s.push(int(do[1]))
    elif operation == 'pop':
        if s.is_empty():
            print('Stack is empty.')
        else:
            print('Popped value: ', s.pop())
    elif operation == 'quit':
        break

Time Complexity Analysis

When we implement Stack using a Queue the push operation becomes expensive.

Push operation: O(n)

Pop operation: O(1)

Please do like


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