In: Statistics and Probability
The amounts of financial aid awarded for a population of students are shown below. Using an appropriate graphical technique, state whether you believe that the assumption of normality of this population of aid awards exists. Justify your answer.
$8,500 $11,000 $12,400 $9,000 $14,000 $4,500 $12,000 $16,000 $7.500 $11,500 $8.000 $19,000 $10,500 $5,000 $16,500 $9,500 $20,000 $17,500 $8.500 $12,500 $7,000 $19,000 $19,500 $6,000 $13,000
We will use normal probability plot to check that is from normal distribution or not.
Normal probability plot-
Observation table -
X | Rank | Cumulative prob | Z |
8500 | 7.5 | 0.28 | -0.58 |
11000 | 12 | 0.46 | -0.1 |
12400 | 15 | 0.58 | 0.2 |
9000 | 9 | 0.34 | -0.41 |
14000 | 18 | 0.7 | 0.52 |
4500 | 1 | 0.02 | -2.05 |
12000 | 14 | 0.54 | 0.1 |
16000 | 19 | 0.74 | 0.64 |
7500 | 5 | 0.18 | -0.92 |
11500 | 13 | 0.5 | 0 |
8000 | 6 | 0.22 | -0.77 |
19000 | 22.5 | 0.88 | 1.17 |
10500 | 11 | 0.42 | -0.2 |
5000 | 2 | 0.06 | -1.55 |
16500 | 20 | 0.78 | 0.77 |
9500 | 10 | 0.38 | -0.31 |
20000 | 25 | 0.98 | 2.05 |
17500 | 21 | 0.82 | 0.92 |
8500 | 7.5 | 0.28 | -0.58 |
12500 | 16 | 0.62 | 0.31 |
7000 | 4 | 0.14 | -1.08 |
19000 | 22.5 | 0.88 | 1.17 |
19500 | 24 | 0.94 | 1.55 |
6000 | 3 | 0.1 | -1.28 |
13000 | 17 | 0.66 | 0.41 |
Cumulative probability = (i - 0.5)/n
where, i = rank of X & n = total sample size
Value of Z calculated from table provided below.
In normal probability plot, points are approximately close to staight line. A straight line in a normal probability plot is a strong indication of data normally distributed.
Hence, the assumption of normality of this population of aid awards exists.