The energy efficency ratio of a refrigerator that consumes 1800 W of electricty to remove 12,000...

The energy efficency ratio of a refrigerator that consumes 1800 W of electricty to remove 12,000 BTU/h of heat does not exceed 3.5. True or False?

Expert Solution

To calculate Energy efficiency ratio (EER) you need to apply the following equation:

EER = Ec / PA

In this case the Ec is 12,000 BTU/h and the Pa is 1800 W so:

EER = 12,000 / 1800 = 6.67

With this value, you may say that the statement is false. However, if you convert BTU/h to kW:

1 BTU/h ---------> 2.931x10^-4 kW

12,000 ------------> x

x = 12,000 * 2.931x10^-4 = 3.51685 kW or 3516.86 W

EER = 3516.86 / 1800

EER = 1.95

According to this last result, the statement would be true.

So, What would be the real and true result?, well, according to definition of EER:

The Energy Efficiency Ratio - EER - is a term generally used to define cooling efficiency of unitary air-conditioning and heat pump system.

The efficiency is determined at a single rated condition specified by an appropriate equipment standard and is defined as the ratio of net cooling capacity - or heat removed in Btu/h - to the total input rate of electric power applied - in Watts. The units of EER are Btu/Wh.

Then, the result would be 6.67 BTU/Wh, so the EER exceed 3.5. The statement is false.

queen_honey_blossom answered 2 years ago

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