Question

In: Chemistry

The following reaction is similar to the breathing cycle of plants: 4KO2(s)   + 2CO2 (g)   ®2K2CO3...

The following reaction is similar to the breathing cycle of plants:

4KO2(s)   + 2CO2 (g)   ®2K2CO3 (s) + 3O2 (g) Calculate change inH for the above reaction from the following data:

change in H (kcal)

K(s)   + O2 (g)   ®KO2 (s)                                                           -134.0

KOH(s)   + CO2 (g)   ®KHCO3(s)                                                -33.5

2KHCO3(s) ®CO2(g) + H2O(g) + K2CO3(s) +33.0

2K(s) + 2H2O(g)   ®2KOH(s) + H2 (g)                                         -88.0

H2 (g)   + 1/2O2(g)   ®H2O(g)                                                      -57.8

Solutions

Expert Solution


4*[ KO2 (s)    -----> K(s)   + O2 (g) ]              DH1 = 4*+134

2*[2KHCO3(s)   ------> CO2(g) + H2O(g) + K2CO3(s)]     DH2 = 2*+33.0

4*[KOH(s)+ CO2(g) ---> KHCO3(s)   ]                    DH3 = 4*-33.5

2*[2K(s) + 2H2O(g) ---> 2KOH(s) + H2 (g) ]           DH4 = 2*-88.0

2*[H2 (g) + 1/2O2(g) ----> H2O(g)   ]                  DH5 = 2*-57.8
-----------------------------------------------------------------------
4KO2(s)   + 2CO2 (g) ---> 2K2CO3 (s) + 3O2 (g) DH = DH1+DH2+DH3+DH4+DH5
------------------------------------------------------------------------

DH = 4*134+2*33.0+4*-33.5+2*-88.0+2*-57.8

     = 176.4 KJ

queen_honey_blossom answered 2 years ago
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