Question

In: Chemistry

One kmol of gaseous octane (C8H18) is ignited with stoichiometric amount of dry air in a...

One kmol of gaseous octane (C8H18) is ignited with stoichiometric amount of dry air in a closed, rigid vessel. The pressure of the reactants is 1 atm and the temperature is 25C; while the temperature of the products is 727C. Assume “complete” combustion.

(a) Calculate the pressure (atm) of the products.

(b) Determine the heat transfer (kJ/kg fuel) during the reaction.

Answer: (a) 3.42 atm

Solutions

Expert Solution

The combustion of C8H18 is given as:

C8H18     +      x (O2 + 3.76 N2)           8 CO2    +    9H2O    +     3.76x N2

Balancing O2 on both sides:

x = 8 + 9/2

x = 12.5

Hence balanced combustion equation will be:

C8H18     +      12.5 O2 + 47 N2           8 CO2    +    9H2O    +     47 N2

(a). Total moles on left side = 1 + 12.5 + 47

= 60.5

Total moles on right side = 8 + 9 + 47

= 64

Temperature of reactants = 25 oC = 298 K

Temperature of products = 727 oC = 1000 K

Using, P1 / n1T1 = P2 / n2T2

1 / (60.5 * 298) = P2 / (64 * 1000)

P2 = (64 * 1000) / (60.5 * 298)

P2 = 3.55 atm

Hence, pressure (atm) of the products = 3.55 atm


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