In: Chemistry
One kmol of gaseous octane (C8H18) is ignited with stoichiometric amount of dry air in a closed, rigid vessel. The pressure of the reactants is 1 atm and the temperature is 25C; while the temperature of the products is 727C. Assume “complete” combustion.
(a) Calculate the pressure (atm) of the products.
(b) Determine the heat transfer (kJ/kg fuel) during the reaction.
Answer: (a) 3.42 atm
The combustion of C8H18 is given as:
C8H18 + x (O2 + 3.76 N2) 8 CO2 + 9H2O + 3.76x N2
Balancing O2 on both sides:
x = 8 + 9/2
x = 12.5
Hence balanced combustion equation will be:
C8H18 + 12.5 O2 + 47 N2 8 CO2 + 9H2O + 47 N2
(a). Total moles on left side = 1 + 12.5 + 47
= 60.5
Total moles on right side = 8 + 9 + 47
= 64
Temperature of reactants = 25 oC = 298 K
Temperature of products = 727 oC = 1000 K
Using, P1 / n1T1 = P2 / n2T2
1 / (60.5 * 298) = P2 / (64 * 1000)
P2 = (64 * 1000) / (60.5 * 298)
P2 = 3.55 atm
Hence, pressure (atm) of the products = 3.55 atm