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In: Chemistry

A 39.7g piece of copper rod is heated to 98 degrees celsius and then placed in...

A 39.7g piece of copper rod is heated to 98 degrees celsius and then placed in an insulated container containing 50.7 grams of water at 18.3 degrees celsius. Assuming no loss of water and using the following parameters, what is the final temperature of the system? Assume that the container is always at the same temperature as that of the water.

Ccopper 0.387(J/gxK) CH2O 4.184(J/gxK) Cvessel 12.30 (J/K)

Solutions

Expert Solution

Heat lose of copper rod                                               =                               Heat gain of water + calorimeter

mcT                                                                         =                             mcT + C*T

39.7*0.387*(98-t)                                                          =                            50.7*4.184*(t-18.3) + 12.3*(t-18.3)

                          t   = 19.6

The final temperature of the mixture = 19.60C

queen_honey_blossom answered 2 years ago
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