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In: Physics

a piece of solid lead weighing 6.5 kg at 327 degrees celsius receives 150000 joules of...

a piece of solid lead weighing 6.5 kg at 327 degrees celsius receives 150000 joules of heat.. in what state is the lead after this occurs? the latent heat of fusion for lead is 23200 J/kg

Solutions

Expert Solution

Weight of solid= 6.5kg

Latent heat of fusion=23200J/Kg

Energy= m*L= 6.5*23200= 150800J

Given energy=150000J

As the given energy is less than energy given by latent heat

So the state of lead is solid

Weight of solid= 6.5kg

Latent heat of fusion=23200J/Kg

Energy= m*L= 6.5*23200= 150800J

Given energy=150000J

As the given energy is less than energy given by latent heat

So the state of lead is solid

Weight of solid= 6.5kg

Latent heat of fusion=23200J/Kg

Energy= m*L= 6.5*23200= 150800J

Given energy=150000J

As the given energy is less than energy given by latent heat

So the state of lead is solid

Weight of solid= 6.5kg

Latent heat of fusion=23200J/Kg

Energy= m*L= 6.5*23200= 150800J

Given energy=150000J

As the given energy is less than energy given by latent heat

So the state of lead is solid

Weight of solid= 6.5kg

Latent heat of fusion=23200J/Kg

Energy= m*L= 6.5*23200= 150800J

Given energy=150000J

As the given energy is less than energy given by latent heat

So the state of lead is solid

genius_generous answered 2 months ago
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