In: Physics
a piece of solid lead weighing 6.5 kg at 327 degrees celsius receives 150000 joules of heat.. in what state is the lead after this occurs? the latent heat of fusion for lead is 23200 J/kg
Weight of solid= 6.5kg
Latent heat of fusion=23200J/Kg
Energy= m*L= 6.5*23200= 150800J
Given energy=150000J
As the given energy is less than energy given by latent heat
So the state of lead is solid
Weight of solid= 6.5kg
Latent heat of fusion=23200J/Kg
Energy= m*L= 6.5*23200= 150800J
Given energy=150000J
As the given energy is less than energy given by latent heat
So the state of lead is solid
Weight of solid= 6.5kg
Latent heat of fusion=23200J/Kg
Energy= m*L= 6.5*23200= 150800J
Given energy=150000J
As the given energy is less than energy given by latent heat
So the state of lead is solid
Weight of solid= 6.5kg
Latent heat of fusion=23200J/Kg
Energy= m*L= 6.5*23200= 150800J
Given energy=150000J
As the given energy is less than energy given by latent heat
So the state of lead is solid
Weight of solid= 6.5kg
Latent heat of fusion=23200J/Kg
Energy= m*L= 6.5*23200= 150800J
Given energy=150000J
As the given energy is less than energy given by latent heat
So the state of lead is solid