In: Chemistry
When a piece of copper, at a temperature of 256.0 degrees Celsius, is added to 255 grams of water at a temperature of 20.0 degrees celsius, the temperature of the resulting mixture is 24.0 degrees celsius. If the specific heat of copper is 0.385 J/g x degrees celsius, what was the mass of the copper? The specific heat of water is 4.184 J/g x degrees celsius.
heat lose of copper = heat gain of water
mcT = mcT
m*0.385*(256-24) = 255*4.184*(24-20)
m = 47.78g
mass of copper = 47.78g >>>>answer