When a piece of copper, at a temperature of 256.0 degrees Celsius, is added to 255...

When a piece of copper, at a temperature of 256.0 degrees Celsius, is added to 255 grams of water at a temperature of 20.0 degrees celsius, the temperature of the resulting mixture is 24.0 degrees celsius. If the specific heat of copper is 0.385 J/g x degrees celsius, what was the mass of the copper? The specific heat of water is 4.184 J/g x degrees celsius.

Solutions

Expert Solution

heat lose of copper = heat gain of water

mcT = mcT

m*0.385*(256-24) = 255*4.184*(24-20)

m = 47.78g

mass of copper = 47.78g >>>>answer

queen_honey_blossom answered 1 year ago

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