Question

In: Chemistry

When a piece of copper, at a temperature of 256.0 degrees Celsius, is added to 255...

When a piece of copper, at a temperature of 256.0 degrees Celsius, is added to 255 grams of water at a temperature of 20.0 degrees celsius, the temperature of the resulting mixture is 24.0 degrees celsius. If the specific heat of copper is 0.385 J/g x degrees celsius, what was the mass of the copper? The specific heat of water is 4.184 J/g x degrees celsius.

Solutions

Expert Solution

heat lose of copper                   =                              heat gain of water

mcT                                      =                               mcT

m*0.385*(256-24)                      =                               255*4.184*(24-20)

m                                                = 47.78g

mass of copper                         = 47.78g >>>>answer


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