In: Statistics and Probability
Life test performed on a sample of 13 batteries of a new model indicated one and average life of 75 months and to a standard deviation of 5 months other battery models produced by similar processes have normally distributed lifespans the 90% confidence interval for the population mean the life of the new model is
Solution :
Given that,
Point estimate = sample mean =
= 75
sample standard deviation = s = 5
sample size = n = 13
Degrees of freedom = df = n - 1 = 12
At 90% confidence level the t is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
t
/2,df = t0.05,12 = 1.782
Margin of error = E = t/2,df
* (s /
n)
= 1.782 * ( 5/
13)
= 2.471
The 90% confidence interval estimate of the population mean is,
- E <
<
+ E
75 - 2.471 <
< 75 + 2.471
72.529 <
< 77.471
The 90% confidence interval for the population mean the life of the new model is (72.529 , 77.471)