In: Math
3. A manufacturer of photographic flash batteries took a sample of 13 batteries from the production of any given day and used them continuously until they were used up. Battery life in hours until it ran out was: 342, 426, 317, 545, 264, 451, 749, 631, 512, 266, 492, 562 and 298. With a significance level of 0.05, there is evidence that the Battery life is more than 400 hours? (assume that life times have normal distribution)
3. For the given data
Create the following table.
data | data-mean | (data - mean)2 |
342 | -108.3846 | 11747.22151716 |
426 | -24.3846 | 594.60871716 |
317 | -133.3846 | 17791.45151716 |
545 | 94.6154 | 8952.07391716 |
264 | -186.3846 | 34739.21911716 |
451 | 0.61540000000002 | 0.37871716000003 |
749 | 298.6154 | 89171.15711716 |
631 | 180.6154 | 32621.92271716 |
512 | 61.6154 | 3796.45751716 |
266 | -184.3846 | 33997.68071716 |
492 | 41.6154 | 1731.84151716 |
562 | 111.6154 | 12457.99751716 |
298 | -152.3846 | 23221.06631716 |
Find the sum of numbers in the last column to get.
So
Now we need test the claim that mean>400
So hypothesis is vs
As sample size is less than 30 and also population standard deviation is not known, we will use t statistics
So
P value is TDIST(1.21,12,1)=0.1248>alpha=0.05
Hence we fail to reject the null hypothesis
Hence we do not have sufficient evidence to support the claim that mean is greater than 400 hours.