In: Statistics and Probability
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 66 type K batteries and a sample of 59 type Q batteries. The mean voltage is measured as 8.62 for the type K batteries with a standard deviation of 0.628, and the mean voltage is 9.01 for type Q batteries with a standard deviation of 0.543. Conduct a hypothesis test for the conjecture that the mean voltage for these two types of batteries is different. Let μ1 be the true mean voltage for type K batteries and μ2 be the true mean voltage for type Q batteries. Use a 0.1 level of significance.
Step 1 of 4 :
State the null and alternative hypotheses for the test.
Step 2 of 4: Compute the value of the test statistic. Round your answer to two decimal places.
Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0. Round the numerical portion of your answer to three decimal places.
Step 4 of 4: Make the decision for the hypothesis test.
A. Reject Null Hypothesis
B. Fail to Reject Null Hypothesis
We want to test that the conjecture that the mean voltage for these two types of batteries is different.
Let μ1 be the true mean voltage for type K batteries
and μ2 be the true mean voltage for type Q batteries.
1) State the null and alternative hypotheses for the test.
Ho:- μ1 = μ2 vs Ha:- μ1 # μ2
2)
A sample of 66 type K batteries
A sample of 59 type Q batteries.
The mean voltage is measured as 8.62 for the type K batteries with a standard deviation of 0.628
The mean voltage is 9.01 for type Q batteries with a standard deviation of 0.543