Question

Write this in c++

Leap year and Second in year program

1. Whether a year is a leap year on not a leap year.
2. The number of seconds in a year. (FYI, it will be a different amount for leap vs non-leap year.) You can calculate the seconds by whatever means you choose, whether with defined constants and calculations or just calculations. It is your choice.
3. If the user inputs a year number greater than zero, the program returns how many seconds were or will be in that year.
4. Put in descriptions for your request for input. If you do the bonus portion, also put that in for your request.
5. Tell the user that an input of -99 ends the program. (+5)
   Put your prompt in a loop, asking the user each time what year to check. (+5)
6. You should assume a day length of exactly 24 hours. Obviously, multiplying 365*24*3600 isn’t exactly a programming challenge, and it won’t even give the right answer for all years.
7. You must take account of leap years, which means your years will not all have the same number of days. If you do not already know, here is the calculation for leap years:

1. If a year is divisible by 4 with no remainder, it is a leap year,
2. unless it is a centurial year (ending in 00).
3. Then it is not a leap year,
4. unless it is a year divisible by 400, in which case it is still a leap year.

For example:

1904 is a leap year—evenly divisible by 4.
1900 is not a leap year—it is evenly divisible by 4, and also evenly divisible by 100. However, it is not evenly divisible by 400.
2000 is a leap year— it is evenly divisible by 4, evenly divisible by 100, but also evenly divisible by 400.
Your calculation should ignore all other variations in the length of the calendar year, such as leap seconds or the change from the Julian to the Gregorian system.

Answer 1

import java.util.Scanner;

public class YearToSeconds {
   public static void main(String[] args) {
       Scanner sc = new Scanner(System.in);
       while (true) {
           System.out.println("Enter year (-99 to quit): ");
           int year = sc.nextInt();
           if(year==-99)
               break;
           long seconds = 0;
           if (isLeap(year))
               seconds = 365 * 24 * 3600;
           else
               seconds = 366 * 24 * 3600;
           System.out.println(year + " has " + seconds + " seconds");
       }
   }

   private static boolean isLeap(int year) {
       boolean leap = false;
       // if any year is divisable by 4 than there are many chances for leap year
       // except few
       if (year % 4 == 0) {
           // if it is divisable by 100 than it shoud also divisable by 400 like 2000 etc
           if (year % 100 == 0) {
               // year is divisible by 400, so the year is a leap year
               if (year % 400 == 0)
                   leap = true;
               else
                   leap = false;
           } else
               leap = true;
       } else
           leap = false;
       return leap;
   }
}

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