Question

In: Statistics and Probability

Consider the hypothesis statement shown below using alphaαequals=0.050.05 and the data to the right from two...

Consider the hypothesis statement shown below using

alphaαequals=0.050.05

and the data to the right from two independent samples.

Upper H 0 : mu 1 minus mu 2 equals 0H0: μ1−μ2=0

Upper H 1 : mu 1 minus mu 2 not equals 0H1: μ1−μ2≠0

​a) Calculate the appropriate test statistic and interpret the result.

​b) Calculate the​ p-value and interpret the result.

x overbarx1

equals=

231231

x overbarx2

equals=

209209

sigmaσ1

equals=

6565

sigmaσ2

equals=

5353

n1

equals=

4444

n2

equals=

3636

Solutions

Expert Solution

Given information:

=231 , =209

=65 , =53

n1 =44 , n2 = 36

Hypothesis :

Two tailed test.

Here population standar deviations are known so we have to use two sample z test.

Test statistic -

z = 1.6676

P-value -

P- value for this two tailed test is,

P-value = 2*P( z >1.6676)

P( z >1.6676) = 1- P( z < 1.6676)

Using excel function,. =NORMSDIST( z)

P( z<1.6676) = NORMSDIST( 1.6676) =0.9523

So P(z > 1.6676)= 1 - 0.9523 = 0.0477

P- value = 2*0.0477 = 0.0954

P-value = 0.0954

Decision about null hypothesis-

Rule - Reject null hypothesis if p-value less than significance level

Here = 0.05

It is observed that p-value (0.0954) greater than significance level

So fail to reject null hypothesis.

Conclusion-

There is sufficient evidence to conclude that there is difference between population means.


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