In: Statistics and Probability
Consider the following hypothesis statement using a = 0.05 and data from two independent samples. Assume the population variances are not equal and the populations are normally distributed. H0: u1 - u2 = 0 H1: u1 - u2 = 0 x1: = 114.7 x2 = 122.0 s1 = 24.6 s2 = 14.3 n1 = 14 n2 20 a. Calculate the appropriate test statistic and interpret the result. b. Approximate the p-value using Table 5 in Appendix A and interpret the results. c. Determine the precise p-value using Excel. d. Verify your results using PHStat..
Ho : µ1 - µ2 = 0
Ha : µ1-µ2 ╪ 0
Level of Significance , α =
0.05
Sample #1 ----> sample 1
mean of sample 1, x̅1= 114.70
standard deviation of sample 1, s1 =
24.6
size of sample 1, n1= 14
Sample #2 ----> sample 2
mean of sample 2, x̅2= 122.000
standard deviation of sample 2, s2 =
14.30
size of sample 2, n2= 20
difference in sample means = x̅1-x̅2 =
114.700 - 122.0000
= -7.3000
std error , SE = √(s1²/n1+s2²/n2) =
7.3110
t-statistic = ((x̅1-x̅2)-µd)/SE = ( -7.3000
/ 7.3110 ) = -0.998
=
19
p-value =
0.3306 (excel function: =T.DIST.2T(t stat,df)
)
Conclusion: p-value>α , Do not reject null
hypothesis
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