In: Economics
Consider the following alternatives:
A |
B |
C |
|
Initial Cost |
$420 |
$780 |
$260 |
Uniform Annual Benefits |
$59 |
$138 |
$49 |
Salvage Value |
$120 |
$225 |
$75 |
Useful Life |
10 |
10 |
10 |
Assume a MARR of 13%.
a) What is the IRR of Alternative A?
b) What is the IRR of Alternative B?
c) What is the IRR of Alternative C?
d) Of A, B, and C, only two meet or exceed the MARR. For those two, what is the DIRR between them?
e) Which Alternative should be selected?
A |
B |
C |
||
Initial Cost |
$420 |
$780 |
$260 |
|
Uniform Annual Benefits |
$59 |
$138 |
$49 |
|
Salvage Value |
$120 |
$225 |
$75 |
|
Useful Life |
10 |
10 |
10 |
a. IRR of Alternative A
MARR = 13%
Using the trial and error method
Calculating PW at 13%
PW = -420 + 59 (P/A, 13%, 10) + 120 (P/F, 13%, 10)
PW = -420 + 59 (5.4262) + 120 (0.2946) = -65
As the NPW is negative decrease MARR to 9% to get positive NPW
NPW at 9% = -420 + 59 (P/A, 9%, 10) + 120 (P/F, 9%, 10)
NPW at 9% = -420 + 59 (6.4177) + 120 (0.4224) = 9
Using interpolation, IRR = 9% + [9 – 0 ÷ 9 – (-65)]*4% = 9.4%
b. IRR of Alternative B?
Using the trial and error method
Calculating PW at 13%
PW = -780 + 138 (P/A, 13%, 10) + 225 (P/F, 13%, 10)
PW = -780 + 138 (5.4262) + 225 (0.2946) = 35
As the NPW is positive increase MARR to 15% to get negative NPW
PW = -780 + 138 (P/A, 15%, 10) + 225 (P/F, 15%, 10)
PW = -780 + 138 (5.0188) + 225 (0.2472) = -32
Using interpolation, IRR = 13% + [35 – 0 ÷ 35 – (-32)]*2% = 14%
c. IRR of Alternative C?
Using the trial and error method
Calculating PW at 13%
PW = -260 + 49 (P/A, 13%, 10) + 75 (P/F, 13%, 10)
PW = -260 + 49 (5.4262) + 75 (0.2946) = 28
As the NPW is positive increase MARR to 16% to get negative NPW
PW = -780 + 138 (P/A, 16%, 10) + 225 (P/F, 16%, 10)
PW = -780 + 138 (4.8332) + 225 (0.2267) = -6
Using interpolation, IRR = 13% + [28 – 0 ÷ 28 – (-6)]*3% = 15.4%
A |
B |
C |
||
Initial Cost |
$420 |
$780 |
$260 |
|
Uniform Annual Benefits |
$59 |
$138 |
$49 |
|
Salvage Value |
$120 |
$225 |
$75 |
|
Useful Life |
10 |
10 |
10 |
|
IRR |
9.4% |
14% |
15.4% |
d. From the above calculation it can be seen that only Alternative B and C can be compared to calculate the incremental IRR because their IRR is greater than MARR. The Alternative A has an IRR that is less than MARR, so it cannot be accepted.
B |
C |
ICF of B - C |
|
Initial Cost |
-$780 |
-$260 |
-520 |
Uniform Annual Benefits |
$138 |
$49 |
89 |
Salvage Value |
$225 |
$75 |
150 |
Calculating PW of ICF of B – C at 13%
PW = -520 + 89 (P/A, 13%, 10) + 150 (P/F, 13%, 10)
PW = -520 + 89 (5.4262) + 150 (0.2946) = 7
As the NPW is positive increase MARR to 14% to get negative NPW
PW = -520 + 89 (P/A, 14%, 10) + 150 (P/F, 14%, 10)
PW = -520 + 89 (5.2161) + 150 (0.2697) = -15
Using interpolation, IRR of ICF of B – C = 13% + [7 – 0 ÷ 7 – (-15)]*1% = 13.3%
e. IRR of B – C is greater than MARR (13%) so select Alternative B.