In: Statistics and Probability
Question 3
A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every bag contains exactly the same weight. But if more than 14% of bags are over-filled then they stop production to fix the machine. They define over-filled to be more than 1 ounce above the weight on the package.
The engineer weighs 175 bags and finds that 56 of them are over-filled. He plans to test the hypotheses H0: p = 0.14 versus Ha: p > 0.14. What is the test statistic?
z =
(Please round your answer to two decimal places if necessary.)
Question 4
A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every bag contains exactly the same weight. But if more than 15% of bags are over-filled then they stop production to fix the machine. They define over-filled to be more than 1 ounce above the weight on the package.
The engineer weighs 100 bags and finds that 21 of them are over-filled. He plans to test the hypotheses H0:p=0.15 versus Ha:p>0.15.
What is the test statistic?
Question 5
Does secondhand smoke increase the risk of a low weight birth? A baby is “low birth weight” if it weighs less than 5.5 pounds at birth. According to the National Center of Health Statistics, about 7.8% of all babies born in the U.S. are categorized as low birth weight. Researchers randomly select 1200 babies whose mothers had extensive exposure to secondhand smoke during pregnancy. 10.4% of the sample are categorized as low birth weight.
Which of the following are the appropriate null and alternative hypotheses for this research question.
Question 6
Short-term classes: Does taking a class in a short-term format (8 weeks instead of 16 weeks) increase a student’s likelihood of passing the course? For a particular course, the pass rate for the 16-week format is 59%. A team of faculty examine student data from 40 randomly selected accelerated classes and determine that the pass rate is 78%.
Which of the following are the appropriate null and alternative hypotheses for this research question?
Question 7
One population proportion test: Which of the following situations involves testing a claim about a single population proportion?
Question 8
According to a Pew Research Center study, in May 2011, 34% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 377 community college students at random and finds that 148 of them have a smart phone. Then in testing the hypotheses:
H0: p = 0.34 versus
Ha: p > 0.34,
what is the test statistic?
z = . (Please round your answer to two decimal places.)
Question 9
According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 349 community college students at random and finds that 138 of them have a smart phone. In testing the hypotheses:
H0: p = 0.33 versus
Ha: p > 0.33,
she calculates the test statistic as z = 2.5990.
Then the p‑value = .
(Please round your answer to four decimal places.)
Q3: n = 175, x = 56
p̄ = x/n = 0.32
Null and Alternative hypothesis:
Ho : p = 0.14 ; H1 : p > 0.14
Test statistic:
z = (p̄ -p)/√(p*(1-p)/n) = (0.32 - 0.14)/√(0.14 * 0.86/175) = 6.86
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Q4: n = 100, x = 21
p̄ = x/n = 0.21
Null and Alternative hypothesis:
Ho : p = 0.15 ; H1 : p > 0.15
Test statistic:
z = (p̄ -p)/√(p*(1-p)/n) = (0.21 - 0.15)/√(0.15 * 0.85/100) = 1.68
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Q5: Null and Alternative hypothesis:
Ho : p = 0.078
H1 : p > 0.078
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Q6: Null and Alternative hypothesis:
Ho : p = 0.59
H1 : p > 0.59
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Q7: Answer: A recent study estimated that 20% of all college students in the United States smoke. The head of Health Services at Goodheart University suspects that the proportion of smokers may be lower there.
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Q8: n = 377, x = 148
p̄ = x/n = 0.3926
Null and Alternative hypothesis:
Ho : p = 0.34 ; H1 : p > 0.34
Test statistic:
z = (p̄ -p)/√(p*(1-p)/n) = (0.3926 - 0.34)/√(0.34 * 0.66/377) = 2.15
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Q9: n = 349, x = 138
p̄ = x/n = 0.3954
Null and Alternative hypothesis:
Ho : p = 0.33 ; H1 : p > 0.33
Test statistic:
z = (p̄ -p)/√(p*(1-p)/n) = (0.3954 - 0.33)/√(0.33 * 0.67/349) = 2.5990
p-value = 1- NORM.S.DIST(2.599, 1) = 0.0047