Question

In: Statistics and Probability

A proponent of a new proposition on a ballot wants to know whether the proposition is...

A proponent of a new proposition on a ballot wants to know whether the proposition is likely to pass. The proposition will pass if it gets more than​ 50% of the votes. Suppose a poll is​ taken, and 560 out of 1000 randomly selected people support the proposition. Should the proponent use a hypothesis test or a confidence interval to answer this​ question? Explain. If it is a hypothesis​ test, state the hypotheses and find the test​ statistic, p-value, and conclusion. Use a 5 ​% significance level. If a confidence interval is​ appropriate, find the approximate 90 ​% confidence interval. In both​ cases, assume that the necessary conditions have been met. Should the proponent use a hypothesis test or a confidence​ interval? (If both a hypothesis test and a confidence interval could be​ used, choose the simpler​ one.) A. The proponent should use a hypothesis test because the proponent wants to know whether or not the proposition will pass. A confidence interval would be useless. B. The proponent should use a hypothesis test because the proponent wants to know whether or not the proposition will pass.​ However, the proponent could also use a confidence interval. C. The proponent should use a confidence interval because the proponent wants to know the proportion of the population who will vote for the proposition. A hypothesis test would be impossible. D. The proponent should use a confidence interval because the proponent wants to know the proportion of the population who will vote for the proposition.​ However, the proponent could also use a hypothesis test. Determine the null and alternative hypotheses for the hypothesis test. Let p denote the population proportion of voters in favor of the proposition. Select the correct choice below​ and, if​ necessary, fill in the answer boxes within your choice. ​(Type integers or decimals. Do not​ round.) A. Upper H 0 ​: pless than nothingUpper H Subscript a ​: pgreater than nothing B. Upper H 0 ​: pequals nothingUpper H Subscript a ​: pgreater than nothing C. Upper H 0 ​: pequals nothingUpper H Subscript a ​: pnot equals nothing D. Upper H 0 ​: pequals nothingUpper H Subscript a ​: pless than nothing E. Upper H 0 ​: pgreater than nothingUpper H Subscript a ​: pless than nothing F. A hypothesis test is not the most appropriate approach. The proponent should use a confidence interval. Find the test statistic for the hypothesis test. Select the correct choice below​ and, if​ necessary, fill in the answer box within your choice. A. zequals nothing ​(Round to two decimal places as​ needed.) B. A hypothesis test is not the most appropriate approach. The proponent should use a confidence interval. Find the​ p-value. Select the correct choice below​ and, if​ necessary, fill in the answer box within your choice. A. ​p-valueequals nothing ​(Round to three decimal places as​ needed.) B. A hypothesis test is not the most appropriate approach. The proponent should use a confidence interval. Determine the proper conclusion to the hypothesis test. Choose the correct answer below. A. Do not reject Upper H 0 . There is not enough evidence to conclude that the proposition will pass. B. Reject Upper H 0 . There is not enough evidence to conclude that the proposition will pass. C. Do not reject Upper H 0 . There is enough evidence to conclude that the proposition will pass. D. Reject Upper H 0 . There is enough evidence to conclude that the proposition will pass. E. A hypothesis test is not the most appropriate approach. The proponent should use a confidence interval. Construct an approximate 90 ​% confidence interval for the population proportion p. Select the correct choice below​ and, if​ necessary, fill in the answer boxes within your choice. A. left parenthesis nothing comma nothing right parenthesis ​(Round to two decimal places as​ needed.) B. A confidence interval is not the most appropriate approach. The proponent should use a hypothesis test. Click to select and enter your answer(s).

Solutions

Expert Solution

Solution:-

B) The proponent should use a hypothesis test because the proponent wants to know whether or not the proposition will pass. However, the proponent could also use a confidence interval.

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: P < 0.50
Alternative hypothesis: P > 0.50

Note that these hypotheses constitute a one-tailed test.

Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method, shown in the next section, is a one-sample z-test.

Analyze sample data. Using sample data, we calculate the standard deviation (S.D) and compute the z-score test statistic (z).

S.D = sqrt[ P * ( 1 - P ) / n ]

S.D = 0.01581
z = (p - P) / S.D

z = 3.795

where P is the hypothesized value of population proportion in the null hypothesis, p is the sample proportion, and n is the sample size.

Since we have a one-tailed test, the P-value is the probability that the z-score is greater than 3.795.

Thus, the P-value = less than 0.0001.

Interpret results. Since the P-value (almost 0) is less than the significance level (0.05), we cannot accept the null hypothesis.

Reject Upper H 0 . There is enough evidence to conclude that the proposition will pass.

90 % confidence interval for the population proportion is C.I = ( 0.534, 0.586).

C.I = 0.56 + 1.645 × 0.01581

C.I = 0.56 + 0.02601

C.I = ( 0.534, 0.586)


Related Solutions

your thoughts about Proposition 15 on the California ballot this November 2020.
your thoughts about Proposition 15 on the California ballot this November 2020.
A public health researcher wants to know whether a new tax that was placed on soda...
A public health researcher wants to know whether a new tax that was placed on soda has had any impact on consumer behavior (whether people continued to buy soda). Before the new tax, convenience stores in the city sold an average of µ = 410, sugar filled beverages per day with σ = 60. The distribution was normal. Following the new tax, data were collected for a sample of n = 9 days and the new mean was M =...
A video game manufacturer has recently released a new game. The manufacturer wants to know whether...
A video game manufacturer has recently released a new game. The manufacturer wants to know whether players rate their new game as more or less difficult than the average difficulty rating of all of their games, μ = 6 and σ = 2. A random sample of 36 players yielded a sample mean of 7 and a standard deviation(s) of 1.8.              a. State the null and alternative hypothesis.              b. Conduct a z-test on the data given.              c. What do you...
A consumer organization wants to know whether there is a difference in the price of a...
A consumer organization wants to know whether there is a difference in the price of a particular toy at three different store types. The price of the toy was checked in a sample of five discount stores, five variety stores, and five department stores. The sample results and the excel output are shown below: Discount Variety Dept. 12 15 19 13 17 17 14 14 16 12 18 20 15 17 19 Anova: Single Factor SUMMARY Groups Count Sum Average...
An advertising company wants to know whether the size of an advertisement and the color of...
An advertising company wants to know whether the size of an advertisement and the color of the advertisement make a difference in the response of magazine readers. A random sample of readers shown ads of 4 different colors and 3 different sizes. Assume that the ratings follow the normal distribution. The rating is shown in the following table: Size of Ad Color of Ad Red Blue Orange Green Small 4 3 3 8 Medium 3 5 6 7 Large 6...
8. (18 pts) A study wants to know whether there is a difference in objection to...
8. (18 pts) A study wants to know whether there is a difference in objection to sharing information among the three groups of customers: customers of insurance companies, customers of pharmacies and customers of medical researchers. A sample of customers is selected for each group and the results are as follows: Organizational Grouping Object to Sharing Information Insurance Pharmacies Research Total Yes 40 80 90 210 No 160 120 110 390 Total 200 200 200 600 At the α =...
A financial advisor wants to know whether there is a significant difference between the NYSE and...
A financial advisor wants to know whether there is a significant difference between the NYSE and NASDAQ markets in the annual dividend rates for preferred stocks. A sample of 30 returns is selected from each market. Assume the two samples are random and independent. Test the claim that there is no difference in the annual dividend rates for the two markets. Use α = 0.05. Expaln how you computed the sample means and standard deviations. Suggestion: use Excel NASDAQ 2.00...
A coffee shop in Victoria wants to know whether there is a significant difference between the...
A coffee shop in Victoria wants to know whether there is a significant difference between the number of lattes sold per day at their Yates St. location and their Johnson St. location. A sample of 31 days at their Yates St. location reveals an average of 22 lattes sold per day with a standard deviation of 5 lattes. A sample of 31 days at their Johnson St. location reveals an average of 19 lattes sold per day with a standard...
A forensic pathologist wants to know whether there is a difference between the rate of cooling...
A forensic pathologist wants to know whether there is a difference between the rate of cooling of freshly killed bodies and those which were reheated, to determine whether you can detect an attempt to mislead a coroner about time of death. He tested several mice for their "cooling constant" both when the mouse was originally killed and then after the mouse was re-heated. Here are the results: Mouse Freshly killed Reheated 1 573 481 2 482 343 3 377 383...
An obstetrician wants to know whether or not the proportions of children born on each day...
An obstetrician wants to know whether or not the proportions of children born on each day of the week are the same. She randomly selects 500 birth records and obtains the data shown in table. Is there reason to believe that the day on which a child is born occurs with equal frequency at the alpha= 0.01. Sunday Monday Tuesday Wednesday Thursday Friday Saturday Observed count (O) 46 76 83 81 81 80 53 PLEASE FOLLOW THE STEPS BELOW: You...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT