In: Statistics and Probability
In a recent survey of 4276 randomly selected households showed that 3549 of them had telephones. Using these results, construct a 99% confidence interval estimate of the true proportion of households with telephones. Use the PANIC acronym
We have given here,      
           
       
          
           
   
x=3549          
           
n=4276          
           
Estimate for sample proportion      
           
       
Level of significance is =1-0.99=0.01  
           
   
Z critical value(using Z table)=2.576