In a recent survey of 4276 randomly selected households showed that 3549 of them had telephones....

In a recent survey of 4276 randomly selected households showed that 3549 of them had telephones. Using these results, construct a 99% confidence interval estimate of the true proportion of households with telephones. Use the PANIC acronym

Expert Solution

We have given here,

x=3549
n=4276
Estimate for sample proportion

Level of significance is =1-0.99=0.01
Z critical value(using Z table)=2.576

orchestra answered 1 year ago

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