In: Statistics and Probability
Like father, like son: In 1906, the statistician Karl Pearson measured the heights of 1078 pairs of fathers and sons. The following table presents a sample of 7pairs, with height measured in inches, simulated from the distribution specified by Pearson.
Father's height |
Son's height |
---|---|
69.0 |
69.1 |
66.7 |
68.8 |
70.1 |
73.3 |
68.3 |
68.3 |
70.7 |
71.0 |
73.6 |
76.5 |
69.3 |
71.4 |
Use the P-value method to test H0:β1=0 versus H1:β1>0. Can you conclude that father's height is useful in predicting son's height? Use the =α0.05 level of significance and the TI-84 calculator.
Compute the least-squares regression line for predicting son's height y from father's height x. Round the slope and y-intercept values to at least four decimal places.
Using Excel, go to Data, select Data Analysis, choose Regression. Put Father's height in X input range and Son's height in Y input range.
SUMMARY OUTPUT | ||||||||
Regression Statistics | ||||||||
Multiple R | 0.898 | |||||||
R Square | 0.806 | |||||||
Adjusted R Square | 0.767 | |||||||
Standard Error | 1.410 | |||||||
Observations | 7 | |||||||
ANOVA | ||||||||
df | SS | MS | F | Significance F | ||||
Regression | 1 | 41.226 | 41.226 | 20.751 | 0.006 | |||
Residual | 5 | 9.934 | 1.987 | |||||
Total | 6 | 51.160 | ||||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | |
Intercept | -13.3792 | 18.575 | -0.720 | 0.504 | -61.127 | 34.368 | -61.127 | 34.368 |
Father's height | 1.2140 | 0.266 | 4.555 | 0.006 | 0.529 | 1.899 | 0.529 | 1.899 |
H0:β1=0 versus H1:β1>0
p-value = 0.006
Since p-value is less than 0.05, we reject the null hypothesis.
So, father's height is useful in predicting son's height.
Regression line: -13.37922+1.2140x
Slope = 1.2140
Intercept = -13.3792