Question
In: Physics
what is the strength of the electric field at the position indicated by the dot in the figure?
what is the strength of the electric field at the position indicated by the dot in the figure?
what is the direction of the electric field at the position indicated by the dot in the figure?
specify the direction as an angle below horizontal
Solutions
Expert Solution
For +1nC charges, kQ = 8.99*10^9 * 1*10^-9 = 8.99
Electric field strength E = kQ / r^2
Electric field direction is radially away from + charges
At the dot:
r1 = 5cm = 0.05m
so E1 = 8.99 / (0.05)^2 N/C = 3596 N/C @ direction angle 0.
E1 = 3596i + 0j
r2 = sqrt(5^2 + 10^2) cm = 11.18 cm = 0.112 m)
so E2 = 8.99 / (0.112)^2 = 719.2 N/C
Angle is 90 - arctan(5/10) = 63.43 deg
E2 = 321.7i + 643.2j
So the net field strength at the dot is
E = E1 + E2 = 3918i + 643.2j = 3970 N/C @ 9.32 deg above horizontal.
genius_generous answered 2 years agoRelated Solutions
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