what is the strength of the electric field at the position indicated by the dot in the figure?

what is the direction of the electric field at the position indicated by the dot in the figure?

specify the direction as an angle below horizontal

Solutions

Expert Solution

For +1nC charges, kQ = 8.99*10^9 * 1*10^-9 = 8.99

Electric field strength E = kQ / r^2

Electric field direction is radially away from + charges

At the dot:

r1 = 5cm = 0.05m

so E1 = 8.99 / (0.05)^2 N/C = 3596 N/C @ direction angle 0.

E1 = 3596i + 0j

r2 = sqrt(5^2 + 10^2) cm = 11.18 cm = 0.112 m)

so E2 = 8.99 / (0.112)^2 = 719.2 N/C

Angle is 90 - arctan(5/10) = 63.43 deg

E2 = 321.7i + 643.2j

So the net field strength at the dot is

E = E1 + E2 = 3918i + 643.2j = 3970 N/C @ 9.32 deg above horizontal.

genius_generous answered 1 year ago

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​what is the strength of the electric field at the position indicated by the dot in the figure?

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what is the strength of the electric field at the position indicated by the dot in the figure?