In: Statistics and Probability
The baseball commissioner believes that the average attendance is less than 2,300,000 per team. You decide to conduct a test of hypothesis to determine whether the mean attendance (Attendance Column) was more than 2,300,000 per team. Use the 5% level of significance. Note: We do not know the populations standard deviation.
Attendance |
2.16 |
2.97 |
2.68 |
2.28 |
3.05 |
1.62 |
3.37 |
2.30 |
4.27 |
1.92 |
2.67 |
1.39 |
2.35 |
2.36 |
2.32 |
2.75 |
3.25 |
2.06 |
2.38 |
1.37 |
3.02 |
3.86 |
2.87 |
3.85 |
3.11 |
1.75 |
2.79 |
3.22 |
3.55 |
1.96 |
Select one:
a. p = .700%. Reject the null. The mean attendance is more than 2.3 million.
b. p = 99.30%. Reject the null. The mean attendance is more than 2.3 million.
c. p = 99.30%. Do not reject the null. The mean attendance is less than 2.3 million.
d. p = .700%. Do not reject the null. The mean attendance is less than 2.3 million.
the test statistic we used here is
S NO | Attendance(x) | ||
1 | 2.16 | -0.49 | 0.2401 |
2 | 2.97 | 0.32 | 0.1024 |
3 | 2.68 | 0.03 | 0.0009 |
4 | 2.28 | -0.37 | 0.1369 |
5 | 3.05 | 0.4 | 0.16 |
6 | 1.62 | -1.03 | 1.0609 |
7 | 3.37 | 0.72 | 0.5184 |
8 | 2.3 | -0.35 | 0.1225 |
9 | 4.27 | 1.62 | 2.6244 |
10 | 1.92 | -0.73 | 0.5329 |
11 | 2.67 | 0.02 | 0.0004 |
12 | 1.39 | -1.26 | 1.5876 |
13 | 2.35 | -0.3 | 0.09 |
14 | 2.36 | -0.29 | 0.0841 |
15 | 2.32 | -0.33 | 0.1089 |
16 | 2.75 | 0.1 | 0.01 |
17 | 3.25 | 0.6 | 0.36 |
18 | 2.06 | -0.59 | 0.3481 |
19 | 2.38 | -0.27 | 0.0729 |
20 | 1.37 | -1.28 | 1.6384 |
21 | 3.02 | 0.37 | 0.1369 |
22 | 3.86 | 1.21 | 1.4641 |
23 | 2.87 | 0.22 | 0.0484 |
24 | 3.85 | 1.2 | 1.44 |
25 | 3.11 | 0.46 | 0.2116 |
26 | 1.75 | -0.9 | 0.81 |
27 | 2.79 | 0.14 | 0.0196 |
28 | 3.22 | 0.57 | 0.3249 |
29 | 3.55 | 0.9 | 0.81 |
30 | 1.96 | -0.69 | 0.4761 |
Total | 79.5 | 15.5414 | |
Mean | 2.65 | ||
S square | 0.5359 | ||
s | 0.7321 |
mean
Variance
now
the Pvalue of Z = 2.6185 is 0.004416
since the p value is less than alpha= 0.05 therefore we reject the null hypothesis and claim that mean is greater than 2.3 million